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3 years ago

For the sign show, select the statements below that describe the situation. Choose all that apply. The system is in equilibrium

Physics

1 answer:

horrorfan [7]3 years ago

3 0

Answer:

A and D

Explanation:

I believe it is A and D because they appear to be the most accurate answers.

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A friend climbs an apple tree and drops a 0.22-kg apple from rest to you, standing 3.5 m below. When you catch the apple, you br

ella [17]

Answer: (A) velocity = 2.8m/s

(B) Average force = 1.9536 Newtons

Explanation:

Find detailed explanation in the attached picture

3 0

3 years ago

A wind generator, such as the one shown , uses the power of wind to generate electricity What do you think is happening inside t

chubhunter [2.5K]

Answer:

The wind spins blades of a wind turbine around a rotor, which spins a generator, which creates electricity (a generator converts mechanical energy into electricity).

5 0

3 years ago

Un montañero de 65kg de masa ha ascendido a la cima del Everest, la montaña más alta del mundo de 8848m de altura sobre el nivel

andrew-mc [135]

Answer:

El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.

Explanation:

Por la definición de trabajo sabemos que el montañero debió contrarrestar trabajo causado por la gravedad terrestre. Si asumimos que el cambio de la altura es muy pequeño en comparación con el radio del planeta (6371 kilómetros vs. 0,5 kilómetros), entonces podemos considerar que la aceleración gravitacional es constante y la ecuación de trabajo ( $\Delta W$ ), medido en joules, que reducida a:

$\Delta W = m\cdot g\cdot \Delta z$ (1)

Donde:

$m$ - Masa del montañero, medido en kilogramos.

$g$ - Aceleración gravitacional, medida en metros por segundo al cuadrado.

$\Delta z$ - Distancia vertical de ascenso del montañero, medida en metros.

Si tenemos que $m = 65\,kg$ , $g = 9,807\,\frac{m}{s^{2}}$ y $\Delta z = 500\,m$ , entonces el trabajo realizado por el montañero para subir es:

$\Delta W = (65\,kg)\cdot \left(9,807\,\frac{m}{s^{2}} \right)\cdot (500\,m)$

$\Delta W = 318727,5\,J$

El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.

7 0

3 years ago

When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees

Naya [18.7K]

Answer:

a) F = 1.26 10⁵ N, b) F = 2.255 10³ N, c) F_ {soil} = 3078 N

Explanation:

For this exercise we will use the relationship between momentum and moment

I = Δp

F t = p_f -p₀

a) with stiff legs, final speed is zero, initial velocity is down

Ft = 0-p₀

F = m v / t

let's calculate

F = 84.0 6.82 / 4.56 10⁻³

F = 1.26 10⁵ N

b) bending the legs

let's calculate

F = 84.0 6.82 / 0.254

F = 2.255 10³ N

c) It is requested to calculate the force of the ground on the man

∑ F = F_soil -W

F_soil = F + W

F_ {soil} = 2.255 103 + 84 9.8

F_ {soil} = 3078 N

3 0

3 years ago

A Carnot engine operates between temperature levels of 600 K and 300 K. It drives a Carnot refrigerator, which provides cooling

KATRIN_1 [288]

Explanation:

Formula for maximum efficiency of a Carnot refrigerator is as follows.

$\frac{W}{Q_{H_{1}}} = \frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{1}}}$ ..... (1)

And, formula for maximum efficiency of Carnot refrigerator is as follows.

$\frac{W}{Q_{C_{2}}} = \frac{T_{H_{2}} - T_{C_{2}}}{T_{C_{2}}}$ ...... (2)

Now, equating both equations (1) and (2) as follows.

$Q_{C_{2}} \frac{T_{H_{2}} - T_{C_{2}}}{T_{C_{2}}}$ = $Q_{H_{1}} \frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{1}}}$

$\gamma = \frac{Q_{C_{2}}}{Q_{H_{1}}}$

= $\frac{T_{C_{2}}}{T_{H_{1}}} (\frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{2}} - T_{C_{2}}})$

= $\frac{250}{600} (\frac{(600 - 300)K}{300 K - 250 K})$

= 2.5

Thus, we can conclude that the ratio of heat extracted by the refrigerator ("cooling load") to the heat delivered to the engine ("heating load") is 2.5.

4 0

3 years ago