Answer:
1. Adding hydrogen gas, b. shift to the right
2. Adding a catalyst, c. No effect
3. Decreasing the pressure, a. shift to the left
Explanation:
Hydrogen gas can be rewritten as H2. Whenever you add something to an equilibrium expression, it will shift to whichever side does not have this. So, since the reactant side has 3 moles of H2, adding more H2 to the reaction will shift to the products side, since there is no H2 there.
Adding a catalyst has no effect on equilibrium reactions.
When decreasing the pressure, equilibrium will shift to the side with the greater number of moles of gas. In this case, there are 4 moles of gas on the left, and 2 on the right, so it would shift to the left.
Answer:
the mass of the glycerine needed in the given solution is 23.92 g
Explanation:
Given;
molarity of the solution (C₃H₈O₃), C = 2.60 M
Volume of the solution, V = 100 mL = 100 x 10⁻³ L = 0.1 M
The molarity of a solution is given as follows;
The molecular mass of the given solution;
molecular mass = (12 x 3) + (8 x 1) + (16 x 3)
molecular mass = 92 g/mol
The mass of the glycerine needed in the given solution is calculated as follows;
reacting mass = amount of solute (moles) x molecular mass (g/mol)
reacting mass = 0.26 x 92
reacting mass = 23.92 g
Therefore, the mass of the glycerine needed in the given solution is 23.92 g
No of moles of MgCl2 = weight of MgCl2 / Molecular weight of MgCl2
Weight of MgCl2 =moles of MgCl2 x molecular mass of MgCl2
= 8.90 x 95=845.5 gm
