Double replacement :
2Na₃PO₄+3CaCl₂⇒6NaCl + Ca₃(PO₄)₂
<h3>Further explanation</h3>
1. A single replacement reaction is a chemical reaction in which one element replaces the other elements of a compound to produce new elements and compounds
2. Double-Replacement reactions. Happens if there is an ion exchange between two ion compounds in the reactant to form two new ion compounds in the product
3. Combination/syntesis : 2 or more reactants combine to form a new compound
4. Decomposition : the reactant is decomposed into 2/more products
If we look at the reaction options available, all of them can be included in the double replacement reaction, but we only choose the reaction from Sodium phosphate and Calcium chloride which leads to options: C because it is balanced (from the number of atoms in the same reactant and product) and is in accordance with the chemical formula of each compound (both products and reactants)
Give the positional isomers of 2 halopropane
(CH3)2CH
answer:
is in file download it
Answer: A volume of 500 mL water is required to prepare 0.1 M
from 100 ml of 0.5 M solution.
Explanation:
Given:
= 0.1 M,
= ?
= 0.5 M,
= 100 mL
Formula used to calculate the volume of water is as follows.

Substitute the values into above formula as follows.

Thus, we can conclude that a volume of 500 mL water is required to prepare 0.1 M
from 100 ml of 0.5 M solution.
Answer:
10.8 ml
Explanation:
The BOD is an empirical test to determine the molecular oxygen used during a specified incubation period (usually five days), for the biochemical degradation of organic matter (carbonaceous demand) and the oxygen used to oxidise inorganic matter.
See attached file
Answer:
a) C4H6+2H2=C4H10
b) 4Na+CF4=4NaF+C
c) 2Na+2NH3=2NaNH2+H2
d) 2H202=2H2O+O2
Explanation:
Try and make sure there is the same number of reactants as products