Answer:
35.5g of sugar
Explanation:
To solve this question we must assume the density of coke = Density of water = 1g/mL
Thus, in a single can of coke, the mass is 355g. Now, the 10% of this coke is sugar. That means the amount of sugar you are consuming is:
355g * (10/100) = 35.5g of sugar
<em>10/100 = 10%</em>
Answer:
Explanation:
what wheres the answer???
Answer:
The energies of combustion (per gram) for hydrogen and methane are as follows: Methane = 82.5 kJ/g; Hydrogen = 162 kJ/g
<em>Note: The question is incomplete. The complete question is given below:</em>
To compare the energies of combustion of these fuels, the following experiment was carried out using a bomb calorimeter with a heat capacity of 11.3 kJ/℃. When a 1.00-g sample of methane gas burned with
<em>excess oxygen in the calorimeter, the temperature increased by 7.3℃. When a 1.00 g sample of hydrogen gas was burned with excess oxygen, the temperature increase was 14.3°C. Compare the energies of combustion (per gram) for hydrogen and methane.</em>
Explanation:
From the equation of the first law of thermodynamics, ΔU = Q + W
Since there is no expansion work in the bomb calorimeter, ΔU = Q
But Q = CΔT
where C is heat capacity of the bomb calorimeter = 11.3
kJ/ºC; ΔT = temperature change
For combustion of methane gas:
Q per gram = (
11.3
kJ/ºC * 7.3°C)/1.0g
Q = 83 kJ/g
For combustion of hydrogen gas:
Q per gram = (
11.3
kJ/ºC * 14.3°C)/1.0g
Q = 162 kJ/g
Ions can be atomic or molecular. If an atom contains either positive or negative charge it said to be atomic cation or atomic anion.
When a molecule carry positive or negative charge it is called as polyatomic cation or polyatomic anion. Generally charged or ionized molecules are called as polyatomic ions.
In given question Fe(HCO₃)₃ ionizes as follow,
Fe(HCO₃)₃ → Fe³⁺ + 3 HCO₃⁻
The Ions produced are Fe³⁺ and HCO₃⁻. Fe³⁺ is said to be atomic (Ferric) ion and HCO₃⁻ (Bicarbonate) is polyatomic ion or molecular ion.
30.6 g of AgNO₃
Explanation:
We have the following chemical reaction:
Na₃PO₄ + 3 AgNO₃ → Ag₃PO₄ + 3 NaNO₃
Now we calculate the number of moles of Na₃PO₄:
number of moles = mass / molecular weight
number of moles of Na₃PO₄ = 9.44 / 164 = 0.06 moles
Now we formulate the following reasoning:
if 1 mole of Na₃PO₄ will react with 3 moles of AgNO₃
then 0.06 moles of Na₃PO₄ will react with X moles of AgNO₃
X = (0.06 × 3) / 1 = 0.18 moles of AgNO₃
mass = number of moles × molecular weight
mass of AgNO₃ = 0.18 × 170 = 30.6 g
Learn more about:
mole concept
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