Kinetic energy depends on the mass and the speed of a moving object.
If the speeds are equal, then the rick with more mass has more kinetic energy.
Hi there!
Angular momentum is equivalent to:

L = angular momentum (kgm²/s)
I = moment of inertia (kgm²)
ω = angular velocity (rad/sec)
Plug in the given values for moment of inertia and angular speed:

Weight of the bus= mass x acceleration due to gravity = 1021x9.8 = 10005.8 N. Hope it helps.
Answer:
The minimun height is 242 [m]
Explanation:
We can solve this problem by using the principle of energy conservation, where potential energy becomes kinetic energy. We will take the point where the Falcon reaches the speed of 69 (m/s), as the point where the potential energy is zero, i.e. it will be the reference point.
At the reference point all potential energy has been transformed into kinetic energy, therefore the kinetic energy can be calculated.
![E_{k}=0.5*m*v^{2} \\ where:\\v = velocity = 69 [m/s]\\m = mass = 480[g] = 0.480[kg]\\E_{k} = kinetic energy [J]\\E_{k} =0.5*0.48*(69)^{2} \\E_{k} =1142.64[J]](https://tex.z-dn.net/?f=E_%7Bk%7D%3D0.5%2Am%2Av%5E%7B2%7D%20%5C%5C%20where%3A%5C%5Cv%20%3D%20velocity%20%3D%2069%20%5Bm%2Fs%5D%5C%5Cm%20%3D%20mass%20%3D%20480%5Bg%5D%20%3D%200.480%5Bkg%5D%5C%5CE_%7Bk%7D%20%3D%20kinetic%20energy%20%5BJ%5D%5C%5CE_%7Bk%7D%20%3D0.5%2A0.48%2A%2869%29%5E%7B2%7D%20%5C%5CE_%7Bk%7D%20%3D1142.64%5BJ%5D)
Now we can calculate the elevation with respect to the reference point using the definition of the potential energy.
![E_{p}=m*g*h\\ E_{p}=E_{k} \\therefore\\h= E_{p}/(m*g)\\h= 1142.64/(.48*9.81)\\h=242[m]](https://tex.z-dn.net/?f=E_%7Bp%7D%3Dm%2Ag%2Ah%5C%5C%20E_%7Bp%7D%3DE_%7Bk%7D%20%5C%5Ctherefore%5C%5Ch%3D%20E_%7Bp%7D%2F%28m%2Ag%29%5C%5Ch%3D%201142.64%2F%28.48%2A9.81%29%5C%5Ch%3D242%5Bm%5D)