Answer: 0.137 m/s
Explanation:
from the question we are given the following
mass of train A (Ma) = 150,000 kg
velocity of train A (Va) = 0.3 m/s
mass of train B (Mb) = 95,000 kg
velocity of train B (Vb) = -0.12 m/s
final velocity (V) = ?
mass of both trains = 245,000 kg
- to solve this question we apply the conservation of momentum
MaVa + MbVb = (Ma + Mb) x V
V = (MaVa + MbVb) / (Ma + Mb)
V = ((150,000 x 0.3) + (95,000 x (-0.12))) / (245,000)
V = -33600 / 245,000
V = 0.137 m/s
Explanation:
Not enough information. It really depends on the technical details of the car ( the data provided is offering just the human factor of the reaction, not the time for getting the impulse through when using the breaks
<span> <span> The answer to your question is: increase the force applied to the object.
Two items are provided as a basis for that conclusion:
1. According to Newton's Second Law of Motion, the formula for finding force is: F = ma
where F is the force,
m is the mass of an object,
and a is the acceleration of the object.
And 2: work = force x distance or W = F x d.</span></span>
Answer:
Explanation:
mass of sled, m = 22 kg
Force of pull, F = 31 N
distance move, d = 53 m
Angle between force and distance, θ = 40°
The formula for the work done is
W = F x d x Cos θ
W = 31 x 53 x cos 40
W = 1258.6 J
Answer:
1°C
Explanation:
Water freezes at 0°C, 32°F, and 273°K.
The only temperature warmer than the freezing point is 1°C.
