To start with solving this
problem, let us assume a launch angle of 45 degrees since that gives out the
maximum range for given initial speed. Also assuming that it was launched at
ground level since no initial height was given. Using g = 9.8 m/s^2, the
initial velocity is calculated using the formula:
(v sinθ)^2 = (v0 sinθ)^2
– 2 g d
where v is final
velocity = 0 at the peak, v0 is the initial velocity, d is distance = 11 m
Rearranging to find for
v0: <span>
v0 = sqrt (d * g/ sin(2 θ)) </span>
<span>v0 = 10.383 m/s</span>
Explanation:
Heat flow = conductivity × area × change in temperature / thickness
q' = kAΔT/t
13.3 W = k (1.56 m²) (7.8°C) / (0.0234 m)
k = 0.0256 W/m/°C
Heat lost by water = heat gained by ice
-mCΔT = mL + mCΔT
-(1000 g) (1 cal/g/°C) (12°C − 37°C) = m (79.7 cal/g) + m (1 cal/g/°C) (12°C − 0°C)
25,000 cal = (91.7 cal/g) m
m = 272.6 g
Answer:
a = - 0.248 m/s²
Explanation:
Frictional drag force
F = ½ *(ρ* v² * A * α)
ρ = density of air , ρ = 1.295 kg/m^3
α = drag coef , α = 0.250
v = 100 km/h x 1000m / 3600s
v = 27.77 m/s
A = 2.20m^2
So replacing numeric in the initial equation
F = ½ (1.295kg/m^3)(27.77m/s)²(2.30m^2)(0.26)
F = 298.6 N
Now knowing the force can find the acceleration
a = - F / m
a = - 298.6 N / 1200 kg
a = - 0.248 m/s²
D) because things that are in motion can have both kinetic and potential energy
