The molecular mass of 
is:
2·1 + 1·32 + 4·16 = 98 g/mol
The amount of solute, expressed by mol, is:
The molar concentration definition is: 
Doing the calculations:
(If you detect any mistakes in my English report me them, please).
Answer:
11.54 M
Explanation:
In this case, all we have to do is to apply the following expression:
M = n/V
M: molarity
n: moles
V: volume of solution in liters
In this case, we can assume that the volume of water will be the volume of solution. This is because the problem is not specifing if the moles of AgNO3 are liquid or solid, so we can make a safe assumption of the volume.
Using the expression above we have:
M = 5.54 / 0.48
M = 11.54 M
This is the molarity of solution
..............................
Answer: Temperature in constant pressure is 286 K
Explanation: If pressure remains constant, then V/T = constant.
V1 = 350 ml and T1 = 200 K and V2 = 500 ml. V1/T1 = V2/T2
and T2 = T1· V2 / V1 = 200 K · 500 ml / 300 ml = 285,7 K
To find the mass of glucose, you must multiply the atomic weight of each of the elements in the molecule by the subscripts in the formula:
Then you add all of them together:
Therefore, the molar weight of glucose is 180.15 grams.
