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Ray Of Light [21]
3 years ago
5

Someone plz hello me ASAP it would be appreciated on question 2 and 3 btw

Chemistry
2 answers:
il63 [147K]3 years ago
6 0

Answer:

2 should be potential energy and 3 should be A

Explanation:

lesya692 [45]3 years ago
6 0
Both should be A. Hope it helps.
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A 3.0 L solution contains 73.5 g of H2SO4. Calculate the molar concentration of the solution.0.25 M0.44 M0.75 M4.0 M
notka56 [123]

The molecular mass of H_2SO_4 is:


2·1 + 1·32 + 4·16 = 98 g/mol


The amount of solute, expressed by mol, is:


73.5\ g\ H_2SO_4\cdot \frac{1\ mol}{98\ g} = 0.75\ mol\ H_2SO_4


The molar concentration definition is: M = \frac{mol\ solute}{volume (L)\ solution}


Doing the calculations:


M = \frac{0.75\ mol}{3\ L} = \bf 0.25\ M


(If you detect any mistakes in my English report me them, please).

6 0
3 years ago
Read 2 more answers
5.54 moles of AgNO3 are dissolved in 0.48 L of water. What is the molarity of the AgNO, solution?
expeople1 [14]

Answer:

11.54 M

Explanation:

In this case, all we have to do is to apply the following expression:

M = n/V

M: molarity

n: moles

V: volume of solution in liters

In this case, we can assume that the volume of water will be the volume of solution. This is because the problem is not specifing if the moles of AgNO3 are liquid or solid, so we can make a safe assumption of the volume.

Using the expression above we have:

M = 5.54 / 0.48

M = 11.54 M

This is the molarity of solution

7 0
4 years ago
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What is the molarity of a solution with 4 moles of solute and 12 liters of solvent?
faltersainse [42]

..............................

6 0
3 years ago
A gas at 200 K occupies a volume of 350 ml. What temperature is needed to increase the volume
Rudik [331]

Answer: Temperature in constant pressure is 286 K

Explanation: If pressure remains constant, then V/T = constant.

V1 = 350 ml and T1 = 200 K and V2 = 500 ml.  V1/T1 = V2/T2

and T2 = T1· V2 / V1 = 200 K · 500 ml / 300 ml = 285,7 K

5 0
3 years ago
Relative formula mass of glucose? (C6H12O6)
Rom4ik [11]

To find the mass of glucose, you must multiply the atomic weight of each of the elements in the molecule by the subscripts in the formula:

C_{6}=6*(12.01g)=72.06g

H_{12}=12*(1.008g)=12.096g

O_{6}=6*(15.999g)=95.994g

Then you add all of them together:

72.06g+12.096g+95.994g=180.15g

Therefore, the molar weight of glucose is 180.15 grams.

3 0
3 years ago
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