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3 years ago

FIRST PERSON WILL BE MARKED BRAINLIEST, THANKED, AND RATED A 5!

Physics

2 answers:

Whitepunk [10]3 years ago

7 0

Answer:

Strong force

Explanation:

The protons and neutrons are in an atom by strong force. It is approximately 137 times stronger than electromagnetic force and 10⁵ times stronger than weak force. Also, it is billion times stronger than gravitational force.

An atom consists of electrons, protons and neutrons. The negatively charged particles are electrons. The positively charged particles are protons. Neutrons have no charge.

Strong force is the strongest attractive force. Hence, the force shown in the diagram is strong force. So, the correct option is (C) " strong ".

svetoff [14.1K]3 years ago

4 0

A is the answer to what your asking

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Let us consider two bodies having masses m and m' respectively.

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From the above we see that F ∝ mm' and $F\alpha \frac{1}{r^{2} }$

Let the orbital radius of planet A is $r_{1}$ = r and mass of planet is $m_{1}$ .

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Hence the gravitational force for planet A is $f_{1} =G \frac{m_{1}*m }{r^{2} }$

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Hence the gravitational force $f_{2} =G\frac{m m_{2} }{r^{2} }$

$f_{2} =G\frac{m*3m_{1} }{[2r_{1}] ^{2} }$

$= \frac{3}{4} G\frac{mm_{1} }{r_{1} ^{2} }$

Hence the ratio is $\frac{f_{2} }{f_{1} } = \frac{\frac{3}{4}G mm_{1/r_{1} ^2} }{Gmm_{1}/r_{1} ^2 }$

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3 years ago

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3 years ago

Two 10-cm-diameter charged rings face each other, 21.0 cm apart. Both rings are charged to +40.0 nC. What is the electric field

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Complete question:

Two 10-cm-diameter charged rings face each other, 21.0 cm apart. Both rings are charged to +40.0 nC. What is the electric field strength at the midpoint between the two rings ?

Answer:

The electric field strength at the mid-point between the two rings is zero.

Explanation:

Given;

diameter of each ring, d = 10 cm = 0.1 m

distance between the rings, r = 21.0 cm = 0.21 m

charge of each ring, q = 40 nC = 40 x 10⁻⁹ C

let the midpoint between the two rings = x

The electric field strength at the midpoint between the two rings is given as;

$E_{mid} = E_{right} +E_{left}\\\\E_{right} = \frac{KQ}{(x^2 + r^2)^\frac{2}{3} } \\\\E_{leftt} = -\ \frac{KQ}{(x^2 + r^2)^\frac{2}{3} }\\\\E_{mid} = \frac{KQ}{(x^2 + r^2)^\frac{2}{3} } - \frac{KQ}{(x^2 + r^2)^\frac{2}{3} } = 0$

Therefore, the electric field strength at the mid-point between the two rings is zero.

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3 years ago

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