Answer:
16.33°C
Explanation:
Applying,
Heat lost by copper = heat gained by water
cm(t₁-t₃) = c'm'(t₃-t₂).............. Equation 1
Where c = specific heat capacity of copper, m = mass of copper, c' = specific heat capacity of water, m' = mass of water, t₁ = initial temperature of copper, t₂ = initial temperature of water, t₃ = final equilibrium temperature.
From the question,
Given: m = 50 kg, t₁ = 140°C, m' = 90 L = 90 kg, t₂ = 10°C
Constant: c = 385 J/kg°C, c' = 4200J/kg°C
Substitute these values into equation 1
50(385)(140-t₃) = 90(4200)(t₃-10)
(140-t₃) = 378000(t₃-10)/19250
(140-t₃) = 19.64(t₃-10)
140-t₃ = 19.64t₃-196.6
19.64t₃+t₃ = 196.4+140
20.64t₃ = 336,4
t₃ = 336.4/20.6
t₃ = 16.33°C
Answer:
(C) deflected toward the top of the page.(
Explanation:
We can answer this problem by using Fleming's Left Hand Rule. By doing so, we have to place:
- The index finger of the left hand in the direction of the magnetic field
- The middle finger of the left hand in the direction of the particle's velocity
- The thumb will give the direction of the force, and therefore the deflection of the proton
In this problem, we have:
- Magnetic field direction: into the page --> index finger
- Proton's velocity: to the right --> middle finger
By doing so, we observe that the thumb points towards the top of the page: therefore, the correct answer is
(C) deflected toward the top of the page.
Answer:
B
Explanation:
The mass of something before it's been processed is the same as it's mass after the process.
Answer:
v = 17.66 m/s
Explanation:
As we know that the lower end of the pole is fixed in the ground and it start rotating about that end
so here we can say that the gravitational potential energy of the pole will convert into rotational kinetic energy of the pole about its one end
so we have
so we have
now we have
now the speed of the other tip of the pole is given as
