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svetlana [45]
4 years ago
6

Distance v. Time

Physics
1 answer:
Allushta [10]4 years ago
3 0

Answer:

4

(m)

2 ( s )

Explanation:

ok...........

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The speed of surface waves in water decreases as the water becomes shallower. Suppose waves travel across the surface of a lake
Elanso [62]

Answer:

The correct solution is "1.2 m".

Explanation:

The given values are:

Wavelength of waves,

λ = 1.5 m

Speed of waves on surface,

V = 2 m/sec

Speed of waves in water,

V₁ = 1.6 m/sec

As we know,

⇒  V=f\times \lambda

or,

⇒  f=\frac{V}{\lambda}

On substituting the values, we get

⇒      =\frac{2}{1.5}

⇒      =1.33 \ Hz

hence,

⇒  \lambda_1=\frac{V_1}{f}

On substituting the values, we get

⇒       =\frac{1.6}{1.33}

⇒       =1.2 \ m

7 0
3 years ago
How do the forces acting on a boat compare to the force acting on a plane ?
erica [24]

Answer:

on there boat there will two main forces act 1,upthrust which comes from water and air and other side on the plane air and gravity.

Explanation:

7 0
3 years ago
Read 2 more answers
18
zhannawk [14.2K]
Average speed= total distance/total time =12km/h
6 0
3 years ago
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fiasKO [112]
The answer to this question is d because prejudices is not based on experience or reasons
3 0
3 years ago
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Consider a uniformly charged non-conducting semicircular arc with radius r and total negative charge Q. The charge on a small se
Mazyrski [523]

Answer: Magnitude of electric field = 6.77×10^11N/C

Explanation: Electric field= E =KQ/ r ^2

Given:

Total charge Q=53.2nc

Radius 84cm= 0.84m

Coulombs constant K= 8.987x10^9NmC^-1

E =(( 8.987×10^9) × 53.2) /(0.84^2)

E = ( 4 . 777 ×10 ^ 9 )/ 0.7056

E = 6.77 × 10^ 11 NC^-1

3 0
3 years ago
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