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3 years ago

Distance v. Time

Physics

1 answer:

Allushta [10]3 years ago

3 0

Answer:

(m)

2 ( s )

Explanation:

ok...........

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Which of the following represents an element?

Digiron [165]

H2 is the correct answer

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2 years ago

A quantum well is a region of semiconductor or metal film that confines particles to a small region, resulting in quantized ener

murzikaleks [220]

Answer:

226.2 m/sec

Explanation:

We have given $\Delta x=510nm=510\times 106{-9}m$

The plank's constant $h=6.67\times 10^{-34}$

Mass of electron $m=9.11\times 10^{-31}kg$

Now according to Heisenberg uncertainty principle $\Delta v\geq \frac{h}{2\pi m\Delta x}$

So $\Delta v\geq \frac{6.6\times 10^{-34}}{2\times 3.14\times 9.11\times 10^{-31}\times 510\times 10^{-9}}=226.2m/sec$

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2 years ago

A Mercedes-Benz 300SL (m = 1700 kg) is parked on a road that rises 15 degrees above the horizontal. What are the magnitudes of (

kogti [31]

Answer: See below

Explanation:

Given:

Mass of the Mercedes-Benz (m) = 1700 kg

Inclination of the road (θ) = 15.0

The free body diagram is shown in figure attached below

a) The normal force is equal to the cos component of the weight of the car.

$\begin{aligned}&f=m g \cos \theta \\&f=1700 \times 9.81 \times \cos 15 \\&f=16108.74 \mathrm{~N}\end{aligned}$

b) The static force will be equal to the weight's sin component.

$\begin{aligned}&f=m g \sin \theta \\&f=1700 \times 9.81 \times \sin 15 \\&f=4316.32 \mathrm{~N}\end{aligned}$

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1 year ago

Currently, is our planet an open or closed system?

Dmitrij [34]

Our planet is closed system because there is a limit of how much matter could be exchanged.

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2 years ago

In certain ranges of a piano keyboard, more than one string is tuned to the same note to provide extra loudness. For example, th

Georgia [21]

Explanation:

Given that,

Frequency in the string, f = 110 Hz

Tension, T = 602 N

Tension, T' = 564 N

We know that frequency in a string is given by :

$f=\dfrac{1}{2L}\sqrt{\dfrac{T}{m/L}}$ , T is the tension in the string

i.e.

$f\propto\sqrt{T}$

$\dfrac{f}{f'}=\sqrt{\dfrac{T}{T'}}$ , f' is the another frequency

${f'}=f\times \sqrt{\dfrac{T'}{T}}$

${f'}=110\times \sqrt{\dfrac{564}{602}}$

f' =106.47 Hz

We need to find the beat frequency when the hammer strikes the two strings simultaneously. The difference in frequency is called its beat frequency as :

$f_b=|f-f'|$

$f_b=|110-106.47|$

$f_b=3.53\ beats/s$

So, the beat frequency when the hammer strikes the two strings simultaneously is 3.53 beats per second.

8 0

2 years ago