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pogonyaev
3 years ago
8

Trumpeter A holds a B-flat note on the trumpet for a long time. Person C is running towards the trumpeter at a constant velocity

. Person B is running away from the trumpeter at the same rate. Person D is standing still the whole time. Which person hears a frequency that is lower than the B-flat?
Physics
2 answers:
goldenfox [79]3 years ago
6 0

Person B hears a note that is lower than a B-flat. This is because as the runner is going away from the stationary trumpeter, the sound waves become elongated, or stretched out. This increases the wavelength and decreases the frequency.

denpristay [2]3 years ago
5 0

Answer:

Person B

Explanation:

Person B will hear the frequency that is lower than the B- flat.

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It is mainly because a solid has a much stronger atom bonds compared to liquid
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Suppose a fireworks shell explodes, breaking into three large pieces for which air resistance is negligible. How is the motion o
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The center of mass isn't affected by the explosion.

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3 0
1 year ago
Law of Conservation of Energy.
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3 0
3 years ago
Which FBD would represent a car moving right with a motor force of 250 N, and force of friction of 750N, a weight of 8500N and a
babymother [125]

Answer:

Option C

Explanation:

Given that

Motor force is 250 N

Force of friction is 750 N

Weight is 8500 N

And, the normal force is 8500 N

Now based on the above information

Here length of the rector shows the relative magnitude forward force i.e. 250 N i..e lower than the frictional force i.e. backward and weight i.e. 8500 would be equivalent to the normal force

8 0
2 years ago
A small sphere has a harge of 9uC and other small sphere has a charge of 4uC.
Helga [31]

Answer:

Electrical force, F = 90 N

Explanation:

It is given that,

Charge on sphere 1, q_1=9\ \mu C=9\times 10^{-6}\ C

Charge on sphere 2, q_1=4\ \mu C=4\times 10^{-6}\ C

Distance between two spheres, d = 6 cm = 0.06 m

Let F is the electrical force between them. It is given by the formula of electric force which is directly proportional to the product of charges and inversely proportional to the square of distance between them such that,

F=k\dfrac{q_1q_2}{d^2}

F=9\times 10^9\times \dfrac{9\times 10^{-6}\times 4\times 10^{-6}}{(0.06)^2}

F = 90 N

So, the electrical force between them is 90 N. Hence, this is the required solution.

7 0
2 years ago
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