Answer:11.602 KW
Explanation:
mass of vehicle
speed=40Km/h
Resistance=600 N
Gear ratio
Net force to overcome by engine is
F=Resistance + sin component of weight
F=600+
Where
F=600+235.38=835.38 N
power=
Engine Power==11.602 KW
Several different loads are going to be used with the voltage divider from Part A. If the load resistances are 300 kΩkΩ , 200 kΩ
kΩ , and 100 kΩkΩ , what is the output voltage that is the most different from the design output voltage vovov_o = 6 VV ? Express your answer in V to three significant figures.
1 answer:
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Answer:
The stress level at which fracture will occur for a critical internal crack length of 6.2mm is 135.78MPa
Explanation:
Given data;
Let,
critical stress required for initiating crack propagation Cc = 112MPa
plain strain fracture toughness = 27.0MPa
surface length of the crack = a
dimensionless parameter = Y.
Half length of the internal crack, a = length of surface crack/2 = 8.8/2 = 4.4mm = 4.4*10-³m
Also for 6.2mm length of surface crack;
Half length of the internal crack = length of surface crack/2 = 6.2/2 = 3.1mm = 3.1*10-³m
The dimensionless parameter
Cc = Kic/(Y*√pia*a)
Y = Kic/(Cc*√pia*a)
Y = 27/(112*√pia*4.4*10-³)
Y = 2.05
Now,
Cc = Kic/(Y*√pia*a)
Cc = 27/(2.05*√pia*3.1*10-³)
Cc = 135.78MPa
The stress level at which fracture will occur for a critical internal crack length of 6.2mm is 135.78MPa
For more understanding, I have provided an attachment to the solution.
Answer:
Power =10004.57kw
Velocity = 296.4m/s
Explanation:
Please see attachment
