Answer:
maneuverability
Explanation:
needless to say, I took the quiz
Answer:
Machinist
Explanation:
A skilled worker with the ability to operate computer numerically controlled (CNC) machines is qualified to work in a machinist position.
A machinist is a person who is properly skilled and consists of advanced knowledge regarding the functions of a CNC machine. He can use different mechanisms and complex numerical functions of the machine to carry out different tasks. Any person who lacks the official learning of mechanisms cannot operate such machines effectively.
Disability is extremely diverse. While some health conditions associated with disability result in poor health and extensive health care needs, others do not. However, all people with disability have the same general health care needs as everyone else, and therefore need access to mainstream health care services.
Answer:
The answer is below
Explanation:
1) The synchronous speed of an induction motor is the speed of the magnetic field of the stator. It is given by:
![n_s=\frac{120f_s}{p}\\ Where\ p\ is \ the \ number\ of\ machine\ pole, f_s\ is\ the\ supply \ frequency\\and\ n_s\ is \ the \ synchronous\ speed(speed \ of\ stator\ magnetic \ field)\\Given: f_s=60\ Hz, p=4. Therefore\\\\n_s=\frac{120*60}{4}=1800\ rpm](https://tex.z-dn.net/?f=n_s%3D%5Cfrac%7B120f_s%7D%7Bp%7D%5C%5C%20Where%5C%20p%5C%20is%20%5C%20the%20%5C%20number%5C%20of%5C%20machine%5C%20pole%2C%20f_s%5C%20is%5C%20the%5C%20supply%20%5C%20frequency%5C%5Cand%5C%20n_s%5C%20is%20%5C%20the%20%5C%20synchronous%5C%20speed%28speed%20%5C%20of%5C%20stator%5C%20magnetic%20%5C%20field%29%5C%5CGiven%3A%20f_s%3D60%5C%20Hz%2C%20p%3D4.%20Therefore%5C%5C%5C%5Cn_s%3D%5Cfrac%7B120%2A60%7D%7B4%7D%3D1800%5C%20rpm)
2) The speed of the rotor is the motor speed. The slip is given by:
![Slip=\frac{n_s-n_m}{n_s}. \\ n_m\ is\ the \ motor\ speed(rotor\ speed)\\Slip = 0.05, n_s= 1800\ rpm\\ \\0.05=\frac{1800-n_m}{1800}\\\\ 1800-n_m=90\\\\n_m=1800-90=1710\ rpm](https://tex.z-dn.net/?f=Slip%3D%5Cfrac%7Bn_s-n_m%7D%7Bn_s%7D.%20%5C%5C%20n_m%5C%20is%5C%20the%20%5C%20motor%5C%20speed%28rotor%5C%20speed%29%5C%5CSlip%20%3D%200.05%2C%20n_s%3D%201800%5C%20rpm%5C%5C%20%5C%5C0.05%3D%5Cfrac%7B1800-n_m%7D%7B1800%7D%5C%5C%5C%5C%201800-n_m%3D90%5C%5C%5C%5Cn_m%3D1800-90%3D1710%5C%20rpm)
3) The frequency of the rotor is given as:
![f_r=slip*f_s\\f_r=0.04*60=2.4\ Hz](https://tex.z-dn.net/?f=f_r%3Dslip%2Af_s%5C%5Cf_r%3D0.04%2A60%3D2.4%5C%20Hz)
4) At standstill, the speed of the motor is 0, therefore the slip is 1.
The frequency of the rotor is given as:
![f_r=slip*f_s\\f_r=1*60=60\ Hz](https://tex.z-dn.net/?f=f_r%3Dslip%2Af_s%5C%5Cf_r%3D1%2A60%3D60%5C%20Hz)
Answer:
Under no circumstances
Explanation:
I'm not 100% sure why, but I remember hearing that you're not suposed to go over the speed limit no matter what