Answer: 24.06°
Explanation:
So,we can say after t if it reaches height h then,
h = (37 sin 53)t - 1/2 * 9.8t^2 (as,vertical component of velocity is 37 sin 53)
Given t = 2s
So, h = 39.5m
And horizontal displacement will be
r = 37 cos 53 *2 = 44.52m
So,after 2s the baseball will be lying 39.57m
above its point of projection and 44.52m ahead of its point of projection.
Now.let the vertical component of velocity will become Vy after time 2s
So, Uy = 37 sin 53- 9.8* 2
or, U = 9.95m/s
And.horizontal component of velocity remains
constant i.e Vx = 37 cos 53 = 22.27m/s
So.magnitude of velocity after 2s is
Square root of (Vx^2 + Vy^2)= 24.4m/s
Making an angle of tan 22.27/9.95 = 24.06°
