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Thepotemich [5.8K]
3 years ago
6

A ball is launched at 24m/s at a 45 degree angle as shown. What is the horizontal component of the velocity (Vx)? (don't include

units)
Physics
1 answer:
zaharov [31]3 years ago
5 0

For the horizontal component <u>we have:</u>

Vx = Vo * cos α

Replacing we have:

Vx = 24 * cos 45°

Resolving:

Vx = 24 * 0.525...

Vx = 12.607

The horizontal velocity is <u>12,607 m/s.</u>

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Which chemical equation represents a double replacement reaction?
liq [111]

D. NaOH + HCI NaCl + H,0

Explanation:

The last option is a double displacement/replacement reaction.

This reaction is a neutralization reaction in which an acid combines with a base to produce salt and water only.

       NaOH    +   HCl   →   NaCl  + H₂O

  • A double displacement reaction is one that occurs between ionic compounds.
  • In this reaction, there is an actual exchange of reaction partners.

One of the following conditions serves as a driving force;

  • Formation of water or any other non-ionizing compound
  • Liberation of gases
  • Formation of a precipitate

learn more:

Precipitate formation brainly.com/question/8896163

#learnwithBrainly

5 0
3 years ago
What would happen if all the waste that the earth produces was put into space would that have a positive or negative effect
vichka [17]
Negative... it would then be in space and eventually killing us for 
1.) it could block the sun and we would slowly freeze to death
and 2.) it could one day find its way back into earth and comes casing into the earth casing a meager food chain mouth-function.
i suck at spelling just fyi.
6 0
3 years ago
What is the average density of a neutron star that has the same mass as the sun but a radius of only 20.0 km?
IrinaK [193]

Answer: 5.935(10)^{13}g/cm^{3}}

Explanation:

Density is a characteristic property bodies and materials, and is defined as the relationship between the mass m and the volume V, as shown below:

D=\frac{m}{V}  (1)

In the case of the neutron star, we know it has the same mass as the Sun:

m=1.989(10)^{30}kg

And its radius is r=20km

On the other hand, if we assume this neutron star has a spherical shape, its volume  can be calculated by the following formula:

V=V_{sphere}=\frac{4}{3}\pir^{3}   (2)

V=\frac{4}{3}\pi(20km)^{3}   (3)

V=33510.321km^{3}   (4)

Substituting (4) in (1):

D=\frac{1.989(10)^{30}kg}{33510.321km^{3}}  (5)

Finally:

D=5.935(10)^{25}kg/km^{3}}=5.935(10)^{13}g/cm^{3}}  

4 0
3 years ago
PART ONE
stira [4]

Answer:

3.64×10⁸ m

3.34×10⁻³ m/s²

Explanation:

Let's define some variables:

M₁ = mass of the Earth

r₁ = r = distance from the Earth's center

M₂ = mass of the moon

r₂ = d − r = distance from the moon's center

d = distance between the Earth and the moon

When the gravitational fields become equal:

GM₁m / r₁² = GM₂m / r₂²

M₁ / r₁² = M₂ / r₂²

M₁ / r² = M₂ / (d − r)²

M₁ / r² = M₂ / (d² − 2dr + r²)

M₁ (d² − 2dr + r²) = M₂ r²

M₁d² − 2dM₁ r + M₁ r² = M₂ r²

M₁d² − 2dM₁ r + (M₁ − M₂) r² = 0

d² − 2d r + (1 − M₂/M₁) r² = 0

Solving with quadratic formula:

r = [ 2d ± √(4d² − 4 (1 − M₂/M₁) d²) ] / 2 (1 − M₂/M₁)

r = [ 2d ± 2d√(1 − (1 − M₂/M₁)) ] / 2 (1 − M₂/M₁)

r = [ 2d ± 2d√(1 − 1 + M₂/M₁) ] / 2 (1 − M₂/M₁)

r = [ 2d ± 2d√(M₂/M₁) ] / 2 (1 − M₂/M₁)

When we plug in the values, we get:

r = 3.64×10⁸ m

If the moon wasn't there, the acceleration due to Earth's gravity would be:

g = GM / r²

g = (6.672×10⁻¹¹ N m²/kg²) (5.98×10²⁴ kg) / (3.64×10⁸ m)²

g = 3.34×10⁻³ m/s²

4 0
3 years ago
What device increases voltage?
erma4kov [3.2K]

Your answer would be C.

A step-up transformer is a transformer that raises voltage from main to secondary by having more secondary winding turns than primary winding turns.

Hope this helps; have a great day!

8 0
3 years ago
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