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Thepotemich [5.8K]

2 years ago

6

A ball is launched at 24m/s at a 45 degree angle as shown. What is the horizontal component of the velocity (Vx)? (don't include

units)

1 answer:

zaharov [31]2 years ago

5 0

For the horizontal component <u>we have:</u>

Vx = Vo * cos α

Replacing we have:

Vx = 24 * cos 45°

Resolving:

Vx = 24 * 0.525...

Vx = 12.607

The horizontal velocity is <u>12,607 m/s.</u>

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