Answer:
vpg = 0.064 N
Explanation:
Upthrust = Volume of fluid displaced
upthrust liquid on the cube g=10ms−2
vpg =0.2 x 0.2 x 0.2 x0.8 x 10= 0.064N
vpg = 0.064 N
hope it helps.
Answer:
PE=mgh
=50×1.5×9.8
=735
Explanation:
need thanks and make me brainiest if it helps you
Answer:
glycolysis is the answer to the question
Answer:
Explanation:
Consider the axis diagram attached.
Given:
Ey = Ez = 0
Eₓ = - 4x N/C · m
Since electric field is in x direction, potential difference would be:
Here we integrate between limits 0 and 4.40 which is distance between A and B along x-axis.
![V_{b} - V_{a} = -4 \left[\begin{array}{ccc}\frac{x^{2} }{2} \end{array}\right]^{4.40}_{0}](https://tex.z-dn.net/?f=V_%7Bb%7D%20-%20V_%7Ba%7D%20%3D%20-4%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cfrac%7Bx%5E%7B2%7D%20%7D%7B2%7D%20%5Cend%7Barray%7D%5Cright%5D%5E%7B4.40%7D_%7B0%7D)
We can use constant acceleration equation to solve for the distance.
Formula is:
Vf^2 = Vi^2 + 2ad
where Vf^2 is final velocity squared, Vi^2 is initial velocity squared, a is acceleration (or deceleration) and d is the distance.
we want the car to come to complete stop, that is, Vf^2 be equal to zero.
Therefore, the equation becomes 0 = Vi^2 + 2ad. Solving for d we get:
d = (-(Vi)^2)/2a). We can ignore the minus sign since acceleration is really deceleration.
We know initial velocity (23m/s) and we know acceleration (max= 300 m/s^2). Plugging these in, we get:
d = ((23 m/s)^2)/(2* 300m/s^2) = <span>0.88m </span>
<span>hope that helps</span>
