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Aleksandr-060686 [28]

2 years ago

14

Why the electric bell will not work if the Electromagnet is replaced with a permanent magnet?

2 answers:

solniwko [45]2 years ago

5 0

As electromagnet are temporary magnets so we can easily change its properties. An electric bell uses an electromagnet which is not a permanent magnet.So the given statement in the problem that a permanent magnet is used in an electric bell is false

maksim [4K]2 years ago

5 0

Electromagnets are temporary magnets. It is composed of a metal core and a loop of coil around it. It acts as a magnet when there is a current running through the coil and acts nothing if there is no current running through the coil.

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A uniform meter rule with a mass of 200g is suspended at zero mark pivotes at 22.0cm mark. calculate the mass of the rule.

denpristay [2]

Answer:

The mass of the rule is 56.41 g

Explanation:

Given;

mass of the object suspended at zero mark, m₁ = 200 g

pivot of the uniform meter rule = 22 cm

Total length of meter rule = 100 cm

0 22cm 100cm

-------------------------Δ------------------------------------

↓ ↓

200g m₂

Apply principle of moment

(200 g)(22 cm - 0) = m₂(100 cm - 22 cm)

(200 g)(22 cm) = m₂(78 cm)

m₂ = (200 g)(22 cm) / (78 cm)

m₂ = 56.41 g

Therefore, the mass of the rule is 56.41 g

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nignag [31]

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3 years ago

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a pulley of diameter 15.0 cm is driven by a motor that revolves at 10 rpm. the pulley drives a 2nd pulley with diameter 10.0 cm.

suter [353]

6.67prm

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3 0

3 years ago

You and your friends find a rope that hangs down 19m from a high tree branch right at the edge of a river. You find that you can

tangare [24]

Answer:

Explanation:

Given

length of rope $L=19\ m$

velocity while running $v=2\ m/s$

when the person jumps off the bank and hang on the rope then we can treat the person as pendulum with Time period T which is given by

$T=2\pi \sqrt{\frac{L}{g}}$

$T=2\pi \sqrt{\frac{19}{9.8}}$

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Greatest Possible distance will be covered when person reaches the other extreme end of assumed pendulum (velocity=zero)

therefore he must hang on for 0.5 T time

$time=0.5\times 8.74=4.37\ s$

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schepotkina [342]

I choose the letter B

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