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Aleksandr-060686 [28]
3 years ago
14

Why the electric bell will not work if the Electromagnet is replaced with a permanent magnet?

Physics
2 answers:
solniwko [45]3 years ago
5 0

As electromagnet are temporary magnets so we can easily change its properties. An electric bell uses an electromagnet which is not a permanent magnet.So the given statement in the problem that a permanent magnet is used in an electric bell is false

maksim [4K]3 years ago
5 0
Electromagnets are temporary magnets. It is composed of a metal core and a loop of coil around it. It acts as a magnet when there is a current running through the coil and acts nothing if there is no current running through the coil.
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PLEASE HELP WITH THIS QUESTION<br><br>What of Newton's 3 laws is this picture​
Reptile [31]

Answer:

Hey

Newtons 1rst law (the penny isint moving, it will remain that way)

7 0
3 years ago
What is the final electron receptor in the light reaction of photosynthesis?
Mumz [18]

Answer: Nicotinamide adenine dinucleotide phosphate (NADP)

Explanation:

<u>Photosynthesis</u> is a metabolic process in which light is transformed into stable chemical energy, converting inorganic matter into organic matter.  

This process is mainly divided in two parts:  

-Light-dependent reactions (also called light reactions)

-Light-independent reactions (also called dark reactions).

In the case of light reactions, the light is used by the plant to produce organic energy molecules, being the coenzyme Nicotinamide adenine dinucleotide phosphate (NADP) the final electron acceptor.

It should be noted, this coenzyme is also involved in the dark phase of photosynthesis, in which carbon dioxide (CO_{2}) is fixed into carbohydrates.

7 0
4 years ago
what is the average speed of (a) a car that travels 400m in 20s. and (b) an athlete who runs 1500m in 4 minutes​
zmey [24]

Answer:

a) 20 m/s

b) 37.5 m)s

Explanation:

Average speed = total distance ÷ total time

=> (a) average speed of a car that travels 400m in 20s

= 400/20 = 20 m/s

& (b) average speed of an athlete who runs 1500m in 4 minutes (or 4×60=240 seconds)

= 1500/240 = 37.5 m/s

5 0
3 years ago
In the long jump, an athlete launches herself at an angle above the ground and lands at the same height, trying to travel the gr
NikAS [45]

A) 2.64t

B) 2.64h

C) 2.64D

Explanation:

A)

The motion of the athlete is equivalent to the motion of a projectile, which consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction

- A uniformly accelerated motion (constant acceleration) along the vertical direction

The time of flight of a projectile can be found from the equations of motion, and it is found to be

t=\frac{2u sin \theta}{g}

where

u is the initial speed

\theta is the angle of projection

g is the acceleration due to gravity

In this problem, when the athlete is on the Earth, the time of flight is t.

When she is on Mars, the acceleration due to gravity is:

g'=0.379 g

where g is the acceleration due to gravity on Earth. Therefore, the time of flight on Mars will be:

t'=\frac{2usin \theta}{g'}=\frac{2u sin \theta}{0.379g}=\frac{1}{0.379}t=2.64t

B)

The maximum height reached by a projectile can be also found using the equations of motion, and it is given by

h=\frac{u^2 sin^2\theta}{2g}

where

u is the initial speed

\theta is the angle of projection

g is the acceleration due to gravity

In this problem, when the athlete is on the Earth, the maximum height is h.

When she is on Mars, the acceleration due to gravity is:

g'=0.379 g

where g is the acceleration due to gravity on Earth. So, the maximum height reached on Mars will be:

h'=\frac{u^2 sin^2\theta}{2g'}=\frac{u^2 sin^2\theta}{(0.379)2g}=\frac{1}{0.379}h=2.64h

C)

The horizontal distance covered by a projectile is also found from the equations of motion, and it is given by

D=\frac{u^2 sin(2\theta)}{g}

where:

u is the initial speed

\theta is the angle of projection

g is the acceleration due to gravity

In this problem, when the athlete is on the Earth, the horizontal distance covered is D.

When she is on Mars, the acceleration due to gravity is:

g'=0.379 g

where g is the acceleration due to gravity on Earth. Therefore, the horizontal distance reached on Mars will be:

D'=\frac{u^2 sin(2\theta)}{g'}=\frac{u^2 sin(2\theta)}{(0.379)g}=\frac{1}{0.379}D=2.64D

7 0
3 years ago
Suppose we are given a square coil that is 5.5 cm on a side containing 100 loops of very fine wire. The total resistance of this
maw [93]

Answer:

I = 578A

Explanation:

The magnitude of the peak value of the induced current flowing in a coild is given by

I = \frac{\epsilon_{max}}{R}

I = \frac{NBA\omega}{R}

Where

I= current

N = Number of loops

\omega = angular velocity

R= Resistance

B = Magnetic field

A = Area

Replacing our values we have that,

I = \frac{(100)(1.3)(0.055)^2(2.5)}{1.7*10^{-3}}

I = 578A

8 0
4 years ago
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