A sample of cobalt-60 has an activity of 2000 Bq. What will the activity be after 10 years? Cobalt-60 has a half life of 5 years
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So, the angular frequency of the blades approximately <u>36.43π rad/s</u>.
<h3>Introduction</h3>Hi ! Here I will discuss about the angular frequency or what is also often called the angular velocity because it has the same unit dimensions. <u>Angular frequency occurs, when an object vibrates (either moving harmoniously / oscillating or moving in a circle)</u>. Angular frequency can be roughly interpreted as the magnitude of the change in angle (in units of rad) per unit time. So, based on this understanding, the angular frequency can be calculated using the equation :
With the following condition :
= angular frequency (rad/s)
= change of angle value (rad)
- t = interval of the time (s)
We know that :
- t = interval of the time = 54.9 s.
What was asked :
Step by step :
So, the angular frequency of the blades approximately 36.43π rad/s.
- T1=40°C=313K
- T_2=-10°C=263K
Applying Charles law
To solve this exercise it is necessary to apply the concepts related to Robert Boyle's law where:
Where,
P = Pressure
V = Volume
T = Temperature
n = amount of substance
R = Ideal gas constant
We start by calculating the volume of inhaled O_2 for it:
Our values are given as
P = 1atm
T=293K
Using the equation to find n, we have:
Number of molecules would be found through Avogadro number, then