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mariarad [96]
3 years ago
13

A sample of cobalt-60 has an activity of 2000 Bq. What will the activity be after 10 years? Cobalt-60 has a half life of 5 years

.
Physics
1 answer:
Luba_88 [7]3 years ago
3 0

Answer:

500.3 Bq

Explanation:

From the formula;

0.693/t1/2 = 2.303/t log (Ao/A)

Where;

t1/12 = half life = 5 years

Ao = initial activity = 2000 Bq

0.693/5 = 2.303/10 log (2000/A)

0.1386= 0.2303  log (2000/A)

0.1386/0.2303 =  log (2000/A)

0.6018 = log (2000/A)

(2000/A) = Antilog (0.6018)

(2000/A) = 3.9976

A = 2000/3.9976

A = 500.3 Bq

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Clouds in our atmosphere cause us to see the different phases of the moon.
krok68 [10]

Answer:

False

Explanation:

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8 0
3 years ago
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A scientist conducting a field investigation records measurements of very low pressure and high relative humidity at the top of
Ivan

Answer:

Please find the answer in the explanation

Explanation:

Given that a scientist conducting a field investigation records measurements of very low pressure and high relative humidity at the top of a mountain.

Since a weather map indicates that a warm front is approaching the mountain, according to the conventional current, the warm front is approaching because the weather must have been in higher relative humidity in cool air.

The warm front is approaching to replace it so that the cool air can conventionally replace the warmth air too.

The condition the scientists will most likely observe at the top of the mountain will be high relative humidity.

5 0
4 years ago
If the relative humidity is 25 nd the saturation mixing ratio is 24g/kg, what is the mixing ratio?
levacccp [35]

The mixing ratio is 6.

To find the answer, we have to know about the mixing ratio.

<h3>What is mixing ratio?</h3>
  • The mixing ratio must be calculated in a complex manner.
  • A saturated vapor pressure (es) for values of air temperature and an actual vapor pressure (e) for values of dewpoint temperature must be determined in order to determine the mixing ratio.
  • The air temperature and/or dewpoint temperature must first be converted to degrees Celsius (°C) before the vapor pressures can be calculated.
  • The equation below can be used to determine the relative humidity (rh), as well as the actual mixing ratio and saturated mixing ratio,

                         Rh=\frac{w}{w_s} *100

where; w is the mixing ratio and w(s) is the saturation mixing ratio.

  • In our question, it is given that,

                                    Rh=25\\w_s=24

  • Thus, the mixing ratio will be,

                            w=\frac{Rh*w_s}{100} =\frac{25*24}{100}=6

Thus, we can conclude that, the mixing ratio is 6.

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5 0
2 years ago
Which of the following statements about price elasticity of demand is​ true?
STatiana [176]

Answer:

B. The elastic portion of a​ straight-line, downward-sloping demand curve corresponds to the segment above the midpoint.

Explanation:

Elasticity measures the sensitivity of one variable to another. Specifically it is a figure that indicates the percentage variation that a variable will experience in response to a variation of another one percent.

The elasticity of demand measures the reaction of demand when one of the factors that affects it varies.

<u>Elasticity - Price of demand.</u>

easure the sensitivity of the quantity demanded to price variations. It indicates the percentage variation that the quantity demanded of a good will experience if its price rises by 1 percent.

<u> Elastic Demand </u>

The demand quantity is relatively sensitive to price variations, so the total expenditure on the product decreases when the price rises, the price elasticity takes value greater than -∞ but less than -1

7 0
3 years ago
An object undergoes two successive displacements:
Gre4nikov [31]

The magnitude of the net displacement is 95.3 m

Explanation:

To find the magnitude of the net displacement, we have to resolve each of the two displacements into the horizontal and vertical direction first.

1st displacement is:

d_1=79 m at 16.9^{\circ}

So its components are

d_{1x}=(79)(cos 16.9^{\circ})=75.6 m\\d_{1y}=(79)(sin 16.9^{\circ})=23.0 m

2nd displacement is:

d_2=16.7 m at 31.1^{\circ}

So its components are

d_{2x}=(16.7)(cos 31.1^{\circ})=14.3 m\\d_{2y}=(16.7)(sin 31.1^{\circ})=8.6 m

Therefore, the x- and y-components of the net displacement are:

d_x=d_{1x}+d_{2x}=75.6+14.3=89.9 m\\d_y=d_{1y}+d_{2y}=23.0+8.6=31.6 m

Therefore, the magnitude of the final displacement is:

d=\sqrt{d_x^2+d_y^2}=\sqrt{(89.9)^2+(31.6)^2}=95.3 m

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8 0
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