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lapo4ka [179]
3 years ago
12

Evaluating an experiment provides a scientist with an opportunity to check for errors in experiment design.

Physics
1 answer:
Lemur [1.5K]3 years ago
5 0
This Sentence is True.

Hope this helps.

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If a 50 kg student is standing on the edge of a cliff. Find the student’s gravitational potential energy if the cliff is 40 m hi
saul85 [17]
The gravitational potential energy:
E p = m x g x h
where m is the mass and h is the height;
m = 50 kg,  g = 9.81 m/s² ,  h = 40 m
E p = 50 kg  x 9.81 m/s²  x  40 m
Answer:
E p = 19,620 J = 19.62 kJ
8 0
3 years ago
Read 2 more answers
Ryan swings a pail of water in a vertical circle 1.0 m in radius at a constant speed. If the water is NOT to spill on him:
nexus9112 [7]

Part 1

If water does not spill at the top point of the circular motion then for the minimum speed condition we can say normal force will be zero at the top position

F_g = ma

mg = m\frac{v^2}{R}

g = \frac{v^2}{R}

v = \sqrt{Rg}

given that

R = 1 m

g = 9.8 m/s^2

now from above equation we have

v = \sqrt{1(9.8)} = 3.13 m/s

Part b)

for minimum value of angular speed we will have

\omega = \frac{v}{R}

\omega = \frac{3.13}{1}

\omega = 3.13 rad/s

3 0
3 years ago
If you ran 15 km/h for 20 min, how much distance would you cover?
nikitadnepr [17]
Since we have 15 kilometers per hour, and we're looking for 20 minutes, let's set up proportions.
20/60 minutes = x/15
20/60 = 1/3, so let's leave that simplified.
1/3 = x/15
Look at the denominators, 3 to 15 is a factor of 5, so multiply the numerator by 5.
1 • 5 = 5, so you will cover 5 kilometers in 20 minutes.

I hope this helps!
4 0
3 years ago
What is the natural pH of the ocean?
Katyanochek1 [597]

Answer: Basic

Explanation: water is "neutral" with a ph of 7, the ocean has like 8 so it is more basic on the scale

7 0
3 years ago
Read 2 more answers
an object moving at 10. km/hr has a kinetic energy of 10. J. what is the kinetic energy of the same object if it is moving at 20
Schach [20]
Kinetic energy is related to velocity by:
KE = (1/2)mv^2

solve for mass m
10 = (1/2)m(10)^2
10 = (1/2)m(100)
10= 50m
10/50 = m
1/5 = m

at 20 km/hr

KE = (1/2)(1/5)(20)^2
KE = (1/10)(400)
KE = 40 J
5 0
3 years ago
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