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asambeis [7]
3 years ago
6

I. The spring does work on the box from the moment the box first hits the spring to the moment the spring first reaches its maxi

mum compression. Indicate whether the work done by the spring is positive, negative, or zero.
Physics
1 answer:
nalin [4]3 years ago
6 0

Answer:

Negative

Explanation:

If the box is heading right in the positive direction, the work will be negative. The spring has an opposite force to that of the box.

Hope this helped. :)

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A double-slit experiment is set up using red light (λ = 706 nm). A first order bright fringe is seen at a given location on a sc
Elanso [62]

Answer:

λ = 470.66 nm

Explanation:

for bright fringey_m = \frac{m\lambda D}{d}

D= distance between slit and screen

d= distance between the slits

for first order bright fringe m = 1,

        y_1 = \frac{1\lambda D}{d}

         y_1 = {706*D}{d}

for dark fringe,we have

y_m = {(m + 1/2)\lambda D}{d}    

Now to get the dark fringes at the same location we should have;

(706)D/d = (m + 1/2)λD/d    

put m = 1

(1 + 1/2)λ = (706)

λ = 470.66 nm

6 0
4 years ago
The law that states that the farther away a galaxy is, the faster it is moving away from us is called ______.
lorasvet [3.4K]

Answer: Hubble's Law

Explanation: Hubble's law that states that the farther away a galaxy is, the faster it is moving away from us

5 0
1 year ago
Three charges 1.5*10-6, 3*10-6, -3*10-6 are placed at three vertices of an equilateral triangle of side 30cm. Find the net force
gulaghasi [49]

Answer:

F = 0N

Explanation:

The force between two charges is given by

F=k\frac{q_1q_2}{r^2}

where r is the distance between the charges and K is the Coulomb's constant

(k=8-89*10^9Nm^2/C^2)

The force in the first charge is only the sum of the forces due to the other charges. Hence we have

F_T=F_1+F_2=k\frac{q_2q_1}{r^2}+k\frac{q_3q_1}{r^2}

F_T=(8.89*10^9\frac{Nm^2}{C^2})\frac{(3*10^{-6}C)(1.5*10^{-6}C)}{(0.3m)^2}+(8.89*10^9\frac{Nm^2}{C^2})\frac{(-3*10^{-6}C)(1.5*10^{-6}C)}{(0.3m)^2}\\\\F_T=0.445N-0.445N=0N

Ft=0N

Hope this helps!!

5 0
3 years ago
Read 2 more answers
when a man travel from hilly region to terai region what will happen to his weight ? explain with reason.​
Sonbull [250]

Answer:

His weight increases.

Explanation:

  • The weight of the body is the gravitational force acting on the body at that location.
  • The gravitational force is defined as the product of mass  of the body and the acceleration due to gravity.

                                           W = m x g

  • The acceleration due to gravity of earth is high at the surface and decreases with respect to the height from the surface.
  • Hence, a man in the higher altitude regions experience lower weight that in the the lower altitude  regions.
8 0
4 years ago
Find the instantaneous acceleration at t=ls for an object moving along a straight axis with velocity function:
Maru [420]
The answer is A.
Explanation:
We know that the average acceleration a for an interval of time Δt is expressed as:

a = Δv
Δt
where Δv is the change in velocity that occurs during Δt.
e formula for the instantaneous acceleration a is almost the same, except that we need to indicate that we're interested in knowing what the ratio of Δv to Δt approaches as Δt approaches zero.

We can indicate that by using the limit notation.

So, the formula for the instantaneous acceleration is:

a = lim Δv
Δt→0 Δt
8 0
3 years ago
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