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Korvikt [17]
3 years ago
15

Please answer this correctly

Mathematics
1 answer:
VladimirAG [237]3 years ago
8 0

Answer:

<em>B) </em>Mia Hamm helped her soccer team at the University of North Carolina at Chapel Hill win four NCAA titels.

Step-by-step explanation:

The first option is an opinion, not a fact.

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If Logan's family can drive 23 1/8 miles on 1 gallon of gas,how far can they drive on 17 gallons
guapka [62]

\bf \begin{array}{ccll} miles&\stackrel{gas}{gallons}\\ \cline{1-2}\\ 23\frac{1}{8}&1\\\\ x&17 \end{array}\implies \cfrac{23\frac{1}{8}}{x}=\cfrac{1}{17}\implies \cfrac{\frac{23\cdot 8+1}{8}}{x}=\cfrac{1}{17}\implies \cfrac{\frac{185}{8}}{x}=\cfrac{1}{17} \\\\\\ \cfrac{\frac{185}{8}}{\frac{x}{1}}=\cfrac{1}{17}\implies \cfrac{185}{8}\cdot \cfrac{1}{x}=\cfrac{1}{17}\implies \cfrac{185}{8x}=\cfrac{1}{17} \\\\\\ 3145=8x\implies \cfrac{3145}{8}=x\implies 393\frac{1}{8}=x

4 0
3 years ago
Simplify the trigonometric expression sin(4x)+2 sin(2x) using Double-Angle
drek231 [11]

Answer:

{ \bf{ =  \sin(4x)  + 2 \sin(2x) }} \\  = { \bf{2 \sin(2x) \cos(2x)   + 4 \sin(x)  \cos(x) }} \\  { \bf{ = 4 \sin(x) \cos(x) . ({ \cos }^{2}  x -  { \sin}^{2} }x) + 4 \sin(x) \cos(x)  }  \\  = { \bf{4 \sin(x) \cos(x)  ( { \cos }^{2}x -  { \sin }^{2}x + 1)  }} \\  = { \bf{4 \sin(x) \cos(x)  }(2 { \cos }^{2} x)} \\  = { \bf{8 \sin(x)  { \cos}^{3}x }}

8 0
3 years ago
State all integer values of x in the interval (-3, 3] that satisfy the following
Galina-37 [17]

(-3,3] is an interval which means that -3 and 3 are not inclusive of the values of x -5/3.

We have given

-3x+4 > 9

Required values of x.

State the values of x within -3 and 3.

subtract 4 from both sides,

-3x+4-4>9-4

<h3>What is the meaning of like terms?</h3>

like terms are terms that have the same variables and powers. The coefficients do not need to match.

Collect Like Terms

-3x > 5

(-3x)(-1)   <   5(-1)

3x  <  -5

Divide both sides by 3

3x/3 < -5/3

x    <   -5/3

(-3,3] is an interval which means that -3 and 3 are not inclusive of the values of x is -5/3.

To learn more about the interval visit:

brainly.com/question/12221823

#SPJ1

3 0
2 years ago
I NEED HELP!! please show all work
PtichkaEL [24]

Take the logarithm of both sides. The base of the logarithm doesn't matter.

4^{5x} = 3^{x-2}

\implies \log 4^{5x} = \log 3^{x-2}

Drop the exponents:

\implies 5x \log 4 = (x-2) \log 3

Expand the right side:

\implies 5x \log 4 = x \log 3 - 2 \log 3

Move the terms containing <em>x</em> to the left side and factor out <em>x</em> :

\implies 5x \log 4 - x \log 3 = - 2 \log 3

\implies x (5 \log 4 - \log 3) = - 2 \log 3

Solve for <em>x</em> by dividing boths ides by 5 log(4) - log(3) :

\implies \boxed{x = -\dfrac{ 2 \log 3 }{ 5 \log 4 - \log 3 }}

You can stop there, or continue simplifying the solution by using properties of logarithms:

\implies x = -\dfrac{ \log 3^2 }{ \log 4^5 - \log 3 }

\implies x = -\dfrac{ \log 9 }{ \log 1024 - \log 3 }

\implies \boxed{x = -\dfrac{ \log 9 }{ \log \frac{1024}3 }}

You can condense the solution further using the change-of-base identity,

\implies \boxed{x = -\log_{\frac{1024}3}9}

5 0
3 years ago
Please help me if you think you're hot beautiful skinny funny kind please help me
ehidna [41]

Answer:

Step-by-step explanation:

y= -5x/2+1

3 0
3 years ago
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