Answer:
Half life of S = 3.76secs
Explanation:
The concept of half life in radioactivity is applied. Half life is the time taken for a radioactive material to decay to half of its initial size.
For part 1 - How much signal will be degraded in 1secs = 1/3.9 = 0.2564
for part 2 - How much signal will be degraded in 1secs = 1/104 = 0.009615
Simply say = 1/3.9 + 1/104 = 0.266015
So both part 1 and part 2 took 1/0.266015 = 3.76secs is the half life of S when both pathways are active
Answer:
P=1113.35 psi
Explanation:
For tank 1
V₁= 6.25 L
P₁=1759 psi
For tank 2
V₂=6.25 L
P₂=467.7 psi
Lets take final pressure is P
The final volume V= 6.25 + 6.25 L = 12.5 L
P V = V₂P₂+V₁P₁
Now by putting the values
P V = V₂P₂+V₁P₁
P x 12.5 = 6.25 x 467.7+6.25 x 1759
P=1113.35 psi
So the final volume of the system will be 1113.35 psi.
Answer:
time=4, answer choice A
time=5.5, answer choice B
Explanation:
This is taken from the kinematic equation, v=vo+(1/2)at^2
Velocity at time 4 = 30+(2.5)(4)^2
Velocity at time 5.5 = 30+(2.5)(5.5)^2
Velocity at time 4 seconds = 70 m/s
Velocity at time 5.5 seconds = 105.63 m/s
It will take 6 hrs since 40•6= 260 I hope this helped
Acceleration = (force) / (mass)
If there is no friction . . .
Acceleration = (200N) / (50 kg) = 4m/s²
Change in speed = (acceleration) x (time) = (4 m/s²) x (10 sec) = 40 m/s
<em>Final speed = (speed of the cart before the force began) + (40 m/s more)</em>
(That's about <em><u>89 mph faster</u></em> than the cart was moving before the force started.)
