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4 years ago

10

What is 18 m/s north an example of?

1 answer:

Mkey [24]4 years ago

8 0

Answer:

It is an example of velocity

Explanation:

It is an example of velocity Don't ask how I know because I do know it I just don't know how to explain it.

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Which one is the best to measure a tree kilometers,millimeters,liters or meters?

oksano4ka [1.4K]

Metres would be best

7 0

3 years ago

A 500 g ball swings in a vertical circle at the end of a 1.4-m-long string. when the ball is at the bottom of the circle, the te

sergij07 [2.7K]

A 500 g ball swings in a vertical circle at the end of a 1.4-m-long string. when the ball is at the bottom of the circle, the tension in the string is 18 n.

6 0

3 years ago

Which equation represents the total energy of a system?

aev [14]

C) Total Energy = Potential Energy + Kinetic Energy

Explanation:

The total energy of a system (also called mechanical energy) is given by:

$E=PE+KE$

where

PE is the potential energy

KE is the kinetic energy

The two types of energy have a different origin:

Potential energy (PE) is the energy possessed by an object due to its position. It is commonly in the form of gravitational potential energy, which is the energy due to the position of the object in the gravitational field, defined as:

$PE=mgh$

where m is the mass of the system, g the acceleration of gravity, h the heigth of the object relative to the ground

Kinetic energy (KE), which is the energy possessed by an object due to its motion. It is calculated as

$K=\frac{1}{2}mv^2$

where m is the mass of the system and v is its speed.

Learn more about kinetic and potential energy:

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#LearnwithBrainly

8 0

3 years ago

In rural areas, water is often extracted from underground by pumps. Consider an underground water source whose free surface is 6

stealth61 [152]

Answer:

W = 9533.09 Watt

Explanation:

given,

diameter of pipe inlet, d₁ = 10 cm

r₁ = 5 cm

diameter of pipe outlet, d₂ = 15 cm

r₂= 7.5 cm

head upto water level is to rise = 60 + 5

= 65 m

flow rate = 0.015 m³/s

we know

A₁ v₁ = A₂ v₂ = Q

π r₁² v₁ = π r₂² v₂ = 0.015

$v_1= \dfrac{r_2^2}{r_1^2} v_2$

$v_1= \dfrac{7.5^2}{5^2} v_2$

$v_1= 2.25 v_2$

$v_2 = \dfrac{0.015}{\pi r_2^2}$

$v_2 = \dfrac{0.015}{\pi 0.075^2}$

v₂ = 0.848 m/s

v₁ = 1.908 m/s

Applying Bernoulli's equation

$P_p = \dfrac{1}{2}\rho (v_2^2-v_1^2)+ \rho g h$

$P_p= \dfrac{1}{2}\times 1000\times (0.848^2-1.908^2)+ 1000\times 9.8\times 65$

$P_p= 635539.32 Pa$

P_p is the pump pressure

Power of the pump

W = P_p x Q

W = 635539.32 x 0.015

W = 9533.09 Watt

6 0

3 years ago

The power output of a laser is measured by its wattage, the number of joules of energy it radiates per second (1 W = 1 J s-1). A

viva [34]

Explanation:

It is given that,

Wavelength of red light, $\lambda=676.4\ nm=676.4\times 10^{-9}\ m$

Power of the laser, $P=300\ mW=0.3\ W$

(a) The energy carried by each photon is given by :

$E=\dfrac{hc}{\lambda}$

$E=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{676.4\times 10^{-9}}$

$E=2.94\times 10^{-19}\ J$

(b) Let n is the number of photons emitted by the laser per second. It can be calculated as :

$n=\dfrac{Power}{Energy\ of\ one\ photon}$

$n=\dfrac{0.3}{2.94\times 10^{-19}}$

$n=1.02\times 10^{18}\ photon/s$

Hence, this is the required solution.

7 0

3 years ago