If the activation energy for a given compound is found to be 42.0 kJ/mol, with a frequency factor of 8.0 × 1010 s-1, what is the
1 answer:
Answer:3480s⁻¹
Explanation:We can solve the following problem using the Arrhenius equation.
Arrhenius equation is given by:
A=Pre-exponential factor or frequency factor
Ea=Activation energy
R=Ideal gas constant
T=Temperature
K=Rate constant
From the Arrhenius equation we can see that the rate constant K is related with the activation energy and frequency factor.
In the question we are given with the following data:
Ea=42KJ/mol=42x 1000 J/mol
A=8.0×10¹ per second
T=298K
R=8.314J/K mol
when we substitute these given values in Arrhenius equation
K=3480s⁻¹
The value of rate constant obtained is 3480s⁻¹.
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