Answer:
![[SO_3]=0.25M](https://tex.z-dn.net/?f=%5BSO_3%5D%3D0.25M)
Explanation:
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In this case, since the integrated rate law for a second-order reaction is:
![[SO_3]=\frac{[SO_3]_0}{1+kt[SO_3]_0}](https://tex.z-dn.net/?f=%5BSO_3%5D%3D%5Cfrac%7B%5BSO_3%5D_0%7D%7B1%2Bkt%5BSO_3%5D_0%7D)
Thus, we plug in the initial concentration, rate constant and elapsed time to obtain:
![[SO_3]=\frac{1.44M}{1+14.1M^{-1}s^{-1}*0.240s*1.44M}\\\\](https://tex.z-dn.net/?f=%5BSO_3%5D%3D%5Cfrac%7B1.44M%7D%7B1%2B14.1M%5E%7B-1%7Ds%5E%7B-1%7D%2A0.240s%2A1.44M%7D%5C%5C%5C%5C)
![[SO_3]=0.25M](https://tex.z-dn.net/?f=%5BSO_3%5D%3D0.25M)
Best regards!
We are given with an element Iron, Fe, with a mass of 235.45 g. We are tasked to solve for its corresponding molar mass in mol. We need to find first the molecular weight of Iron, that is
Fe= 55.845 g/mol
With 235.45 g sample, its corresponding mol is
mol Fe= 235.45 g x 1 mol/55.845 = 4.22 mol Fe
Therefore, molar mass of Iron is 4.22 mol
Explanation:
It is known that rate of effusion of gases are inversely proportional to the square root of their molar masses.
And, half of the helium (1.5 L) effused in 24 hour. So, the rate of effusion of He gas is calculated as follows.
= 0.0625 L/hr
As, molar mass of He is 4 g/mol and molar mass of
is 32 g/ mol.
Now,

= 2.83
or, rate of
= 
Rate of
= 0.022 L/hr.
This means that 0.022 L of
gas effuses in 1 hr
So, time taken for the effusion of 1.5 L of
gas is calculated as follows.
= 68.18 hour
Thus, we can conclude that 68.18 hours will it take for half of the oxygen to effuse through the membrane.
Answer:
Ca(ClO3)2
Explanation:
The chemical formula of calcium chlorate is Ca(ClO3)2, which means in this molecule, Ca2+ ion is bonded to two ClO3- ions. So the formula can be expended to O3Cl-Ca-ClO3, or CaCl2O6 (basically times the numbers of the elements inside the bracket by the number outside the bracket.