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Elza [17]
3 years ago
10

How do hydroelectric dams emit greenhouse gases like methane without burning any fossil fuels?

Chemistry
1 answer:
Helen [10]3 years ago
8 0

Answer: The concept behind hydroelectric power is simple: Rather than combusting fossil fuels, like coal, oil, or natural gas, which put over 52 million kilotons of greenhouse gases into the atmosphere each year, dams block the water flowing in rivers or lakes and use the force of the would-be flow to turn turbines,

Explanation:

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If one were asked to choose between paper or plastic which would be chosen and which one would benefit the environment?
vekshin1
It would be plastic Becaus we can recreate things with plastic and other things that are recyclable. Since,we mostly cut down trees everyday for paper,not knowing that we are wasting natural resources, and destroying animal homes and food.
6 0
4 years ago
Give an example of one type of energy conversion (change to another form). Be sure to explain your example.
Daniel [21]
Potential to Kinetic Energy. 
When you a basketball in your hand that is potential energy. Then, when you bounce the ball that is kinetic energy. 
3 0
3 years ago
Which groups of the periodic table want to gain electrons? What kind(s) of elements are these groups
lukranit [14]

Answer:

Elements that are metals tend to lose electrons and become positively charged ions called cations. Elements that are nonmetals tend to gain electrons and become negatively charged ions called anions. Metals that are located in column 1A of the periodic table form ions by losing one electron.

Explanation:

6 0
3 years ago
How many grams of P4O10 would be produced when 0.700 mole of phosphorus is burned?
AysviL [449]
We can solve the equation and show the solution below:

Oxygen atomic number is 16.
Phosphorus atomic number is 32.

We have the molecular weight:
Molecular weight = (31*4) + (16*10)
Molecular weight = 284 grams/mol

Solving for the grams:

0.4 mole (for P4) * (1 mol P4O10/1 mol P4) * (284 grams P4O10/1 mole P4O10)
Total grams = 113.6

The answer is 113.6 grams.
8 0
3 years ago
The exhaust gas from an automobile contains 3% by volume of carbon monoxide (CO). Express this concentration in mg/m3 at 25oC an
ser-zykov [4K]

Answer:

24540\frac{mg}{m^3}

Explanation:

Hello,

In this case, since the 3% by volume is represented as:

\frac{3L\ CO}{L\ gas}

By using the ideal gas equation we compute the density of CO:

\rho =\frac{MP}{RT} =\frac{28g/mol*1atm}{0.082\frac{atm*L}{mol*K}*298K}= 0.818g/L

Then we apply the conversion factors as follows:

=\frac{3L\ CO}{100L\ gas}*\frac{0.818g\ CO}{1L\ CO} *\frac{1000mg\ CO}{1g\ CO} *\frac{1000L\ gas}{1m^3\ gas} \\\\=24540\frac{mg}{m^3}

Regards.

4 0
3 years ago
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