Answer:
C. disposition and condensation
Explanation:
Answer:
Partial pressure of CO₂ is 406.9 mmHg
Explanation:
To solve the question we should apply the concept of the mole fraction.
Mole fraction = Moles of gas / Total moles
We have the total moles of the mixture, if we have the moles for each gas inside. (3.63 moles of O₂, 1.49 moles of N₂ and 4.49 moles of CO₂)
Total moles = 3.63 mol O₂ + 1.49 mol N₂ + 4.49 mol CO₂ = 9.61 moles
To determiine the partial pressure of CO₂ we apply
Mole fraction of CO₂ → mol of CO₂ / Total moles = P. pressure CO₂ / Total P
Partial pressure of CO₂ = (mol of CO₂ / Total moles) . Total pressure
We replace values: (4.49 moles / 9.61 moles) . 871 mmHg = 406.9 mmHg
Answer:lumerman.com › catchphrases › catchphrase
Welcome true believers! The first step to being a superhero is to have a superhero catchphrase to yell out ... I am Danger Boy, the Mighty, Loud, Confidant of Might!!! 02/23/21 ... I am cobalt, the Dynamic, Unbeatable, Hero of Hono
Explanation:
Answer:
I would say the answer is 2
The question is incomplete, complete question is:
A fluid occupying 
of volume has a mass of 4 Mg. Calculate its density and specific volume in SI, EE, and BG units.
Explanation:
1) Mass of liquid = m = 4 Mg = 4 × 1,000 kg = 4,000 kg
(1 Mg = 1000 kg)
Volume of the fluid = V =
Density of the fluid = D
Specific volume is the reciprocal of the density :
Specific volume of the fluid = 
2)
Density of the fluid in English Engineering units = D 
1 kg = 2.20462 lb
1 m = 3.280 ft
Specific volume of the fluid :
3)
Density of the fluid in British Gravitational System units = D 
1 kg = 0.06852 slug
1 m = 3.280 ft
Specific volume of the fluid :
