Answer: The partial pressure of the dry oxygen is 742 torr
Explanation:
Dalton's Law of Partial Pressure states that the total pressure exerted by a mixture of gases is the sum of partial pressure of each individual gas present. Thus 
Given; Total pressure = 762 torr
partial pressure of water = 19.8 torr
partial pressure of dry oxygen = ? torr
Total pressure = partial pressure of water + partial pressure of dry oxygen
762 torr = 19.8 torr = partial pressure of dry oxygen
partial pressure of dry oxygen = 742 torr
The partial pressure of the dry oxygen is 742 torr
Answer:
It's false
Explanation:
Mixtures are always combinations of the same compounds that are at different states.
Answer:
The answer to your question is V2 = 333.9 ml
Explanation:
Data
Pressure 1 = P1 = 1.977 atm
Volume 1 = V1 = 517.4 ml
Pressure 2 = P2 = 3.063 atm
Volume 2 = V2 = ?
Process
To solve this problem use Boyle's law
P1V1 = P2V2
-Solve for V2
V2 = P1V1/P2
-Substitution
V2 = (1.977 x 517.4) / 3.063
-Simplification
V2 = 1022.9 / 3.063
-Result
V2 = 333.9 ml
We are going to use this formula:
Q = M*C*ΔT
when Q is the heat required
M is the mass of CCl4 = 10.35 g
C is the specific heat capacity of CCl4 = 0.874J/g.c
and ΔT the change in temperature = 56.4 - 32.1 °C =24.3 °C
∴ Q = 10.35g * 0.874 * 24.3 °C
= 219.8 J
