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ASHA 777 [7]
2 years ago
5

A double-blind study is one in which neither the researchers nor the subjects know wether the subject is receiving the real trea

tment or the placebo. What is the value of this kind of study?
A. Neither the subjects nor the researchers can bias the results.
B. The researchers cannot replace the placebo with the the real treatment for their favorite subjects.
C. The subjects are not irritated by the fact that they are not receiving the real treatment.
D. Neither the subjects nor the researchers are able to interpret the results.
Chemistry
2 answers:
TEA [102]2 years ago
7 0

Answer:

A. Neither the subjects nor the researchers can bias the results.

Explanation:

As described, a double- blind study is one in which the researcher and his study does not know the person receiving the actual treatment.

Researchers can be bias in their studies as they seek to establish and fine tune results in the way the best favors them. A double-blind study helps to bridge this gap to prevent bias that might be introduced into an experimental set up or while interpreting results.

11111nata11111 [884]2 years ago
3 0

The correct answer is A. Neither the subjects nor the researchers can bias the results.

Explanation:

In regular research studies, the subjects or researchers can manipulate the results or bias these, this in the case of the researches occurs when they manipulate the results of the study based on their interests, prejudices, etc. Also, subjects can manipulate consciously or unconsciously the results if they know whether they are in the group with the treatment or the placebo. However, if neither the subjects nor the researchers know about sho is receiving the treatment of the placebo as it occurs in a double-blind study, they will be more objective and would not manipulate the study or bias the results. Thus, one value of this kind of study is "Neither the subjects nor the researchers can bias the results".

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Draw the product formed when the compound shown below undergoes a reaction with hcl in ch2cl2.
Taya2010 [7]
 The product formed  when HCl and CH2Cl2 react  is   CH4
         H
     H-C- H    methane structure 
         H

  HCl    react with CH2Cl2  to form  methane (CH4) and chlorine gas(Cl2)
that is,

2HCl(g)  + CH2Cl2(l)  = CH4 (g) +2Cl2 (g)
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3 years ago
If acetic acid is the only acid that vinegar contains (ka=1.8×10−5), calculate the concentration of acetic acid in the vinegar.
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CH_{3}COOH \ \textless \ ---\ \textgreater \   H^{+} + CH_{3}COO^{-}

In this case pH value of the solution is necessary to calculate the concentration but it's not given here so pH = 2.88 (looked it up)

pH = 2.88 ==> [H^{+}]  = 10^{-2.88} =  0.001 moldm^{-3}

The change in Concentration Δ [CH_{3}COOH]= 0.001 moldm^{-3}


                                  CH3COOH          H+           CH3COOH    
Initial  moldm^{-3}                      x           0                     0
                                                                                                                       
Change moldm^{-3}        -0.001            +0.001           +0.001
                                                                                                       
Equilibrium moldm^{-3}      x- 0.001      0.001             0.001
                                                                              

Since the k_{a} value is so small, the assumption 
[CH_{3}COOH]_{initial} = [CH_{3}COOH]_{equilibrium} can be made.

k_{a} = [tex]= 1.8*10^{-5}  =  \frac{[H^{+}][CH_{3}COO^{-}]}{[CH_{3}COOH]} =  \frac{0.001^{2}}{x}

Solve for x to get the required concentration.

note: 1.)Since you need the answer in 2SF don&t round up values in the middle of the calculation like I've done here.

         2.) The ICE (Initial, Change, Equilibrium) table may come in handy if you are new to problems of this kind

Hope this helps! 



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Mazyrski [523]

Answer:

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