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4 years ago

What is the value of 200 Kelvin in the Celsius scale of temperature? 100ºC 373ºC -73ºC 73ºC -300ºC

Chemistry

2 answers:

marta [7]4 years ago

4 0

Answer: Option (c) is the correct answer.

Explanation:

It is known that if we have to convert temperature from kelvin to degree celsius then we have to subtract 273 from the given value of temperature.

Whereas when we have to convert temperature from degree celsius to kelvin then we have to add 273 in the given value of temperature.

Therefore, convert value of 200 Kelvin in the Celsius scale of temperature as follows.

Temperature = (200 - 273) degree celsius

= - 73 degree celsius

Thus, we can conclude that value of 200 Kelvin in the Celsius scale of temperature is - $73^{o}C$ .

Levart [38]4 years ago

3 0

-73.15 °C i hope this helps you

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What do the subscripts mean in a molecular formula ?

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Answer:

A molecular formula tells us what atoms and how many of each type of atom are present in a molecule.

Explanation:

If only one atom of a specific type is present, no subscript is used.

For atoms that have two or more present, a subscript is written after the symbol for that atom.

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What is hydrogen role in nuclear fusion?

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3 years ago

What is the pH of a 0.640 M solution of C₅H₅NHBr (Kb of C₅H₅N is 1.7 × 10⁻⁹)?

Elden [556K]

The pH of a 0.64 M solution of pyridine (C₅H₅N) is 9.52.

A figure expressing the acidity or alkalinity of a solution on a logarithmic scale on which 7 is neutral, lower values are more acid and higher values more alkaline.

The equation for the protonation of the base pyridine is the following:

C₅H₅N + H₂O ⇄ C₅H₅NH⁺ + OH⁻ (1)

Kb = 1.7 × 10⁻⁹ (Given)

To calculate the pH of the solution we need to use the following equation:

pH + pOH = 14

=14 - [-log[OH⁻]]

= 14 + log[OH⁻]

Now, we need to find the concentration of the OH⁻ ions. Since pyridine is a weak base, at the equilibrium we have (eq 1):

C₅H₅N + H₂O ⇄ C₅H₅NH⁺ + OH⁻

0.64 - x x x

After entering the values of [C₅H₅N] = 0.64-x, [C₅H₅NH⁺] = x, and [OH⁻] = x, into equation (2) we can find the concentration of OH⁻:

1.7 × 10⁻⁹ =[C₅H₅NH⁺] [OH⁻] / [C₅H₅N]

= x . x / 0.64-x

1.7 × 10⁻⁹ (0.64-x) - x² = 0

Solving the above quadratic equation for x, we have :

x₁ = -3.32 x 10⁻⁵
x₂ = 3.32 x 10⁻⁵

Now, We can calculate the pH, after taking the positive value, x₂, (concentrations cannot be negative) and entering into above equation :

<em />

<em>pH = </em>14 + log[OH⁻]

= 14 + log (3.32 x 10⁻⁵)

= 9.52

Therefore, the pH of the solution of pyridine is 9.52.

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2 years ago

Part II. The molality of a solution is the number of moles of the solute that is dissolved in 1000 g of solvent. Using the value

Aleks [24]

Answer:

Explanation:

The molality of a solution, m is defined as the number of moles of the solute that is dissolved in 1 kg of solvent.

m = number of moles/kilogram of solvent

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3 years ago

An acetic acid buffer containing 0.50 M acetic acid (CH3COOH) and 0.50 M sodium acetate (CH3COONa) has a pH of 4.74. What will t

ad-work [718]

Answer:

pH = 4.71

Explanation:

We can find the pH of a buffer (Mixture of weak acid: CH3COOH, and its conjugate base: CH3COONa) using H-H equation:

pH = pKa + log [CH3COONa] / [CH3COOH]

<em>Where pH is the pH of the buffere = 4.74, pKa the pka of the buffer and [] could be taken as the moles of each reactant.</em>

As initially [CH3COONa] = [CH3COOH], [CH3COONa] / [CH3COOH] = 1:

pH = pKa + log 1

4.74 = pKa

To solve this question we need to find the initial moles of each species, The CH3COONa reacts with HCl to produce CH3COOH. That means the moles of CH3COOH after the reaction are: Initial CH3COOH + Moles HCl

Moles CH3COONa: Initial CH3COONa - Moles HCl.

<em>Moles CH3COOH: </em>

0.100L * (0.50mol / L) = 0.050 moles CH3COOH + 0.0020 moles HCl =

0.052 moles CH3COOH

<em>Moles CH3COONa: </em>

0.100L * (0.50mol / L) = 0.050 moles CH3COONa - 0.0020 moles HCl =

0.048 moles CH3COONa

Using H-H equation:

pH = 4.74 + log [0.048 moles] / [0.052 moles]

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3 years ago