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Zigmanuir [339]

3 years ago

7

the stability of atomic nuclei is related to the _____. ratio of protons to electrons ratio of neutrons to protons number of pro

tons and neutrons number of electrons

2 answers:

jenyasd209 [6]3 years ago

6 0

<span>ratio of neutrons to protons</span>

Dmitry [639]3 years ago

5 0

The stability of atomic nuclei is related to the _____.

<u><em>ratio of neutrons to protons .</em></u>
<u><em> number of protons and neutrons.</em></u>

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Suppose you are trying to separate three Proteins using Gel-Filtration chromatography. The sizes of each are given below:

Damm [24]

<u>Answer:</u> The correct answer is Protein B.

<u>Explanation:</u>

Gel-filtration chromatography is a separation technique that is based on the size of the molecules in a compound. It is also known as size-exclusion chromatography in which the eluent (carrier) used is an aqueous solution.

The matrix that is used is a porous material. When the sample is inserted in the column, the smaller particles interact strongly with the matrix than the large ones. Thus, as the eluent is passed through the matrix, larger molecules come out first, and the smallest molecule comes out last.

Given sizes of the proteins:

Protein A: 1200 kDa

Protein B: 2000 kDa

Protein C: 800 kDa

As protein B has the largest size of all the given proteins, it will emerge out first from the column.

Hence, the correct answer is Protein B.

3 0

2 years ago

What is back titration?

Yakvenalex [24]

Answer:

Back titration is a titration done in reverse; instead of titrating the original sample, a known excess of standard reagent is added to the solution, and the excess is titrated.

I hope it's helpful!

3 0

2 years ago

Which statement best describes how matter and energy is cycled through the ecosystem?

sasho [114]

D. Matter and energy are the same.

3 0

3 years ago

Which of the following situations contains an example of a chemical reaction?

bogdanovich [222]

A bicycle rusting after it is left in the rain is an example of a chemical reaction because it involves oxidation (Option d).

<h3>What is a chemical reaction?</h3>

A chemical reaction can be defined as a phenomenon in which one or more substances called reactants react to form one or more different compounds, which are known as products.

A chemical reaction may include an enzyme that works to increase the seed of the reaction in normal conditions by lowering the activation energy of the reaction.

Therefore, we can conclude that a chemical reaction such as oxidation in a bicycle is a process where reactants combine or break down to form the products of such reaction.

Complete question:

Which of the following situations contains an example of a chemical reaction?

a. Ice forming after water is placed in a freezer

b. Watercolor paint drying on paper

c. a sugar cube dissolving in a glass of water

d. a bicycle rusting after it is left in the rain

Learn more about chemical reactions here:

brainly.com/question/11231920

#SPJ1

6 0

1 year ago

onsider the following reaction: CaCN2 + 3 H2O → CaCO3 + 2 NH3 105.0 g CaCN2 and 78.0 g H2O are reacted. Assuming 100% efficiency

mestny [16]

Answer : The excess reactant is, $H_2O$

The leftover amount of excess reagent is, 7.2 grams.

Solution : Given,

Mass of $CaCN_2$ = 105.0 g

Mass of $H_2O$ = 78.0 g

Molar mass of $CaCN_2$ = 80.11 g/mole

Molar mass of $H_2O$ = 18 g/mole

Molar mass of $CaCO_3$ = 100.09 g/mole

First we have to calculate the moles of $CaCN_2$ and $H_2O$ .

$\text{ Moles of }CaCN_2=\frac{\text{ Mass of }CaCN_2}{\text{ Molar mass of }CaCN_2}=\frac{105.0g}{80.11g/mole}=1.31moles$

$\text{ Moles of }H_2O=\frac{\text{ Mass of }H_2O}{\text{ Molar mass of }H_2O}=\frac{78.0g}{18g/mole}=4.33moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$CaCN_2+3H_2O\rightarrow CaCO_3+2NH_3$

From the balanced reaction we conclude that

As, 1 mole of $CaCN_2$ react with 3 mole of $H_2O$

So, 1.31 moles of $CaCN_2$ react with $1.31\times 3=3.93$ moles of $H_2O$

From this we conclude that, $H_2O$ is an excess reagent because the given moles are greater than the required moles and $CaCN_2$ is a limiting reagent and it limits the formation of product.

Left moles of excess reactant = 4.33 - 3.93 = 0.4 moles

Now we have to calculate the mass of excess reactant.

$\text{ Mass of excess reactant}=\text{ Moles of excess reactant}\times \text{ Molar mass of excess reactant}(H_2O)$

$\text{ Mass of excess reactant}=(0.4moles)\times (18g/mole)=7.2g$

Thus, the leftover amount of excess reagent is, 7.2 grams.

8 0

3 years ago