The answer is B because the equation unmakes
Answer:
a) 3.0076 E24 atoms
Explanation:
∴ mass Cl2 = 354.22 g
∴ molar mass Cl2 = 70.906 g/mol
⇒ mol Cl2 = (354.22 g)*(mol/70.906 g) = 4.9956 mol
⇒ atoms Cl2 = (4.9956 mol)*(6.022 E23 atoms/mol)
⇒ atoms Cl2 = 3.008 E24 atoms
Answer:
≈ 708
Explanation
Here we have equation as:
4 Al + 3 O₂ → 2 Al₂O₃
As we know:
No of moles = Mass/ Molar mass
Here, Mass is 375 g and Molar mass is 27 gms, so no. of moles of Al will be:
=375 g /27 g/mol
= 13.889 mol
About mole ratio, we can see that for 4 moles of Al , 2 moles of Al2O3 are formed, so for 13.889 moles of Al, 13.889 mol ÷ 2 =6.944 moles of Al₂O₃ will be formed.
As we know:
Mass= No of moles/Molar mass
Mass of Al₂O₃ = 6.944 mol × 102 g/mol
= 708.288 g
Hope it helps!
M is the unit for concentration (C)
The units for concentration is mol/ L
To find moles you would have to multiply concentration x volume to cancel out the volume and find get moles (n)
For ex:
Moles (n) = C x V (concentration x volume)
N = 1.23 mol/L x 5L (vol. gets cancelled out)
N = 6.15 moles (you get left with moles)
OR to find concentration:
C = 6.15 moles / 5L
C = 1.23 mols/L OR 1.23 M
