The solution is impossible because when the apply the right equation for electrical power, the current obtained is 0.83 A and not 11.4 A
<h3>What is power?</h3>
This is defined as the rate in which energy is consumed. Electrical power is expressed mathematically as:
Power (P) = voltage (V) × current (I)
P = IV
With above formula, we can obtain the current drawn by the bulb. Details below
<h3>How to determine the current flowing in the circuit</h3>
From the question given, the following data were obtained:
- Power (P) = 100 W
- Voltage (V) = 120 V
- Current (I) =?
P = IV
Divide both sides by V
I = P / V
I = 100 / 120
I = 0.83 A
Thus, we can see that the current drawn by the bulb is 0.83 A and not 11.4 A
From the above, we can see clearly why the inquisitive physics student' calculation is wrong.
Learn more about electrical power:
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The work dine should br like 4x the amount it stared as
The efficiency of a machine indicates how well its input energy is converted to useful output energy or work. It is a major factor in the usefulness of a machine and is the fraction or percentage of the output divided by the input.
According to the Law of Conservation of Energy, the total output energy or work must equal the total input energy. However, some of the input energy does not contribute to the output work and is lost to such things as friction and heat.
Examples of machine efficiency include a lever, automobile, and perpetual motion machine.
Answer:
false.
Explanation:
We know that for a wave that moves with velocity V, with a wavelength λ, and a frequency f, we have the relation:
V = λ*f
So, if the velocity is constant and we increase the frequency to:
f' > f
we will have a new wavelength λ'
Such that:
V = f'*λ'
And V = f*λ
Then we have:
f'*λ' = f*λ
Solvinf for λ', we get:
λ' =(f/f')*λ
And because:
f' > f
then:
(f/f') < 1
Then:
λ' =(f/f')*λ < λ
So, if we increase the frequency, we need to decrease the wavelength.
So, for higher frequency waves, we must have proportionally shorter wavelengths.
Then we can conclude that the given statement:
"or waves moving through the atmosphere at a constant velocity, higher frequency waves must have proportionally longer wavelengths"
is false.