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3 years ago

3 What is happening in this graph from point B to C?

Physics

1 answer:

neonofarm [45]3 years ago

8 0

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VashaNatasha [74]

The answer to the question is A

6 0

3 years ago

Read 2 more answers

A 5400 kg elephant sees a mouse and turns the opposite direction with 8000N of force. What is the elephant's acceleration?

OlgaM077 [116]

Answer:

acceleration= force / mass

a= 1.48 m/sec^2

3 0

4 years ago

Pendulum A has a bob of mass m hung from the string of length L; pendulum B is identical to A except its bob has the length 2L.

GenaCL600 [577]

Answer:

$f_{B}: f_{A} = \sqrt{\frac{2}{1}}$

Explanation:

For pendulum A: Length = L and gravity = g

The frequency of pendulum A is given by

$f = \frac{1}{2\pi }\sqrt{\frac{g}{L}}$

Here, f is the frequency, L be the length

$f_{A} = \frac{1}{2\pi }\sqrt{\frac{g}{L}}$ ... (1)

For pendulum B: Length = 2L, gravity = g

The frequency of pendulum B is given by

$f_{B} = \frac{1}{2\pi }\sqrt{\frac{g}{2L}}$ .... (2)

Divide equation (1) by (2)

$f_{B}: f_{A} = \sqrt{\frac{2}{1}}$

5 0

3 years ago

A rock falls from a tower that is 320 feet high. As it is falling, its height is given by the formula h equals 320 minus 16 t s

RSB [31]

Answer:

a. 4.5secs

Explanation:

From the question, the equation describing the height is given by

$h(t)=320-16t^{2}\\$

at the point when the rock hit the ground, the height,h will be zero.

Hence we can have

$h(t)=320-16t^{2}\\\\at h(t)=0\\0=320-16t^{2}\\hence \\320=16t^{2}\\t^{2}=\frac{320}{16}\\ t^{2}=20\\t=\sqrt{20}\\ t=4.47secs\\t=4.5sec\\$

hence the rock will hit the ground in 4.5secs

4 0

4 years ago

A block of plastic in the shape of a rectangular solid that has height 8.00 cm and area A for its top and bottom surfaces is flo

kifflom [539]

Answer:

0.35 kg

Explanation:

8 cm = 0.08 m

For the block to stay balance, the buoyancy force must be the same as gravity that pulls it down.

Let mass of the block be M, then the gravity would be Mg

Let water density be $\rho_w = 1000 kg/m^3$ , the buoyancy force would be the weight of water that is displaced by the submerged block.

For example, when there is no coin, block is $h_0 = 0.0312m$ submerged. The weight of water displaced must be

$W_0 = Ah_0\rho_wg = 0.0312A1000g = 31.2Ag$

Which is also the weight of block, of Mg

Therefore M = 31.2A. (1)

As coins are stacked on top of block, h increase, so as weight of water displaced and total weight of block and coins. Now let m be the total weight of coins. The gravity of block and weight must be (M+m)g. And the weight of water displaced is:

$W = Ah\rho g = (M + m)g$

$h = \frac{M}{A\rho} + \frac{m}{A\rho}$

Since the linear plot of h vs m has a slope of 0.089 m/kg, we can interpret it as

$\frac{1}{A\rho} = 0.089$

$A = \frac{1}{0.089\rho} = \frac{1}{89} = 0.011 m^2$

So from the eq. (1) we can solve for M = 31.2A = 0.35 kg

8 0

3 years ago