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2 years ago

Is position a base or derived quantity?

Physics

1 answer:

amid [387]2 years ago

8 0

Position is measured in meters (m), so it is a base quantity.

<h3>What is base quantity?</h3>

A base or fundamental quantity is a physical quantity, in which other quantities are derived from.

Example of fundamental quantities;

Mass
Length (position)
Time
Temperature
Amount of substance

<h3>What is a derived quantity?</h3>

Derived quantities are those quantities obtained or expressed from fundamental quantities.

Example of derived quantities;

Speed
Acceleration
Volume
Area
Density, etc

Thus, we can conclude that position measured in meters (m) is a base quantity.

Learn more about base quantities here: brainly.com/question/14480063

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A projectile is launched at an angle of 29 degrees above the horizontal with an initial velocity of 36.6 at an unknown height.

fgiga [73]

The vertical velocity of the projectile upon returning to its original is 17. 74 m/s

<h3>How to determine the vertical velocity</h3>

Using the formula:

Vertical velocity component , Vy = V * sin(α)

Where

V = initial velocity = 36. 6 m/s

α = angle of projectile = 29°

Substitute into the formula

Vy = 36. 6 * sin ( 29°)

Vy = 36. 6 * 0. 4848

Vy = 17. 74 m/s

Thus, the vertical velocity of the projectile upon returning to its original is 17. 74 m/s

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brainly.com/question/24949996

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8 0

2 years ago

How much is required to accelerate a 5kg mass at 20 m/s2

zhannawk [14.2K]

use F = ma

F : force m : mass a : acceleration

f = 5kg * 20 m/s2 = 100 N

5 0

3 years ago

Crickets Chirpy and Milada jump from the top of a vertical cliff. Chirpy drops downward and reaches the ground in 2.70 s, while

Vinvika [58]

Answer:

Explanation:

Given

Time taken to reach ground is $t=2.7\ s$

Malda initial velocity $u=95\ cm/s$

Let h be the height of Cliff

using $h=ut+\frac{1}{2}at^2$

where, u=initial velocity

t=time

In first case chirpy drop downward thus u=0

$h=0+\frac{1}{2}(9.8)(2.7)^2$

$h=35.72\ m$

For Milada there is horizontal velocity u=95 cm/s=0.95 m/s[/tex]

time taken to reach the ground will be same so distance traveled in this time with 0.95 m/s horizontal velocity is given by

$R=u\times t$

$R=0.95\times 2.7=2.43\ m$

7 0

3 years ago

Two lasers are shining on a double slit, with slit separation d. Laser 1 has a wavelength of d/20, whereas laser 2 has a wavelen

xxTIMURxx [149]

Answer:

A) first laser

B) 0.08m

C) 0.64m

Explanation:

To find the position of the maximum you use the following formula:

$y=\frac{m\lambda D}{d}$

m: order of the maximum

λ: wavelength

D: distance to the screen = 4.80m

d: distance between slits

A) for the first laser you use:

$y_1=\frac{(1)(d/20)(4.80m)}{d}=0.24m\\$

for the second laser:

$y_2=\frac{(1)(d/15)(4.80m)}{d}=0.32m$

hence, the first maximum of the first laser is closer to the central maximum.

B) The difference between the first maximum:

$\Delta y=y_2-y_1=0.32m-0.24m=0.08m=8cm$

hence, the distance between the first maximum is 0.08m

C) you calculate the second maximum of laser 1:

$y_{m=2}=\frac{(2)(d/20)(4.80m)}{d}=0.48m$

and for the third minimum of laser 2:

$y_{minimum}=\frac{(m+\frac{1}{2})(\lambda)(D)}{d}\\\\y_{m=3}=\frac{(3+\frac{1}{2})(d/15)(4.80m)}{d}=1.12m$

Finally, you take the difference:

$1.12m-0.48m=0.64m$

hence, the distance is 0.64m

3 0

3 years ago

How long does it take to do 300 Joules of work with 10 watts of power? 30 sec 20 sec .03 sec .30 sec

Oksana_A [137]

Answer:

Explanation:

Power=work /time

10watts=300J/time

Time =30 sec

4 0

3 years ago