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2 years ago

A hydrocarbon molecule has seven carbon

Chemistry

1 answer:

Damm [24]2 years ago

8 0

Answer: Option (3) is the correct answer.

Explanation:

When a linear chain of carbon and hydrogen atoms is attached by single bonds only then it is known as alkane.

When a linear chain of carbon and hydrogen atoms contains a double bond then it is known as alkene.

When a linear chain of carbon and hydrogen atoms contains a triple bond then it is known as alkyne.

Therefore, in the given description there is a double bond between third and fourth carbon. Hence, the IUPAC name of given compound is 3-heptene.

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In a college of exactly 2940 students, exactly 60 % are male. What is the number of female students?

Norma-Jean [14]

Answer:1176

Explanation:

Number of male students: 2940*(60/100)=1764

So the number of female students would be:

2940-1764=1176

5 0

3 years ago

Read 2 more answers

The first eighteen chemical elements on the periodic table are described below in a series of statements. The first 1S letters o

Aleonysh [2.5K]

Answer: The questions looks unclear

Explanation: Periodic table is a table that contains elements arranged according to their increasing atomic number.

1. D belongs to group 4

E. Belongs to group 7

B belongs to group 1

A belongs to group 8. A noble gas.

R belongs to group 3. K belongs to group 6 C belongs to group 1. H belongs to group 8

3 0

3 years ago

What is the name of MnO3

vodka [1.7K]

Answer:

MnO3 radical anion. Formula: MnO3- Molecular weight: 102.9368.

5 0

3 years ago

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On the addition of HI

victus00 [196]

Answer:

$CH_3-CH(I)-CH(CH_3)-CH_3$

$I-CH_2-CH_2-CH(CH_3)-CH_3$

Explanation:

Given the compound $CH_2=CH-CH(CH_3)-CH_3$

The steps of reaction:

$HI \longrightarrow H^+ + I^-$

$CH_2=CH-CH(CH_3)-CH_3 + H^+ \longrightarrow CH_3-CH^+-CH(CH_3)-CH_3$

<u>But this intermediate product has a resonance: </u>

$CH_3-CH^+-CH(CH_3)-CH_3 \longleftrightarrow C^+H_2-CH2-CH(CH_3)-CH_3$

The reaction with I-

$CH_3-CH^+-CH(CH_3)-CH_3 + I^- \longrightarrow CH_3-CH(I)-CH(CH_3)-CH_3$

$C^+H_2-CH2-CH(CH_3)-CH_3 + I^- \longrightarrow I-CH_2-CH_2-CH(CH_3)-CH_3$

8 0

3 years ago

Help plzzzzzzzzzzzzz

tatuchka [14]

Answer:

A: element B

B: element A

C: element B

D: element A

Explanation:

decrease in size leads increase in electronegativity because the smaller the size, the closer the shell is to the nucleus. Also, atomic radius decreases to the right and up on the periodic table. Atomic radius increases to the left and down a period. I hope this helps!

6 0

3 years ago