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11111nata11111 [884]
3 years ago
13

Plz help quick

Chemistry
2 answers:
vovangra [49]3 years ago
4 0

Answer:

3

Explanation:

If oxygen reacts with iron, then both must be reactants and rust the product of that reaction

mariarad [96]3 years ago
4 0

Answer:

4Fe → 3O2 + 2Fe2O3

Explanation:

We see that the equation balances

There are  4 atoms of Iron (Fe) on the left and 2*2 = 4 on the right.

3 * 2 = 6 of oxygen on the left and 2 * 3 = 6 on the right.

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A hot lump of 39.9 g of iron at an initial temperature of 78.1 °C is placed in 50.0 mL H 2 O initially at 25.0 °C and allowed to
Drupady [299]

Answer : The final temperature of the mixture is 29.6^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron = 0.499J/g^oC

c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of iron = 39.9 g

m_2 = mass of water  = Density\times Volume=1g/mL\times 50.0mL=50.0g

T_f = final temperature of mixture = ?

T_1 = initial temperature of iron = 78.1^oC

T_2 = initial temperature of water = 25.0^oC

Now put all the given values in the above formula, we get

(39.9g)\times (0.499J/g^oC)\times (T_f-78.1)^oC=-(50.0g)\times 4.18J/g^oC\times (T_f-25.0)^oC

T_f=29.6^oC

Therefore, the final temperature of the mixture is 29.6^oC

8 0
3 years ago
Perform the following calculations to the correct number of significant figures.
SSSSS [86.1K]
Answer: 460.624

Explanation:
1. Multiply the numbers
(24.5260 x 2.56) + 397.84
= (62.784) + 397.84

2. Add the numbers
(62.784) + 397.84
= 460.624
4 0
2 years ago
Oxygen and hydrogen are both elements that are found as gases at room temperature. When oxygen combines with hydrogen, they prod
Tom [10]

Answer:

A

Explanation:

has properties that are different from the original substances.

5 0
3 years ago
How many moles of ammonia (nh3 will be produced from 4.0 moles of nitrogen (n2?
Lana71 [14]
Standard equation would be N2(g)+3H2(g)==>2NH3(g), so through stoichiometry, (4 mol N2)(2mol NH3/1 mol N2), assuming excess H2, would yield 8 moles of NH3.  
3 0
3 years ago
If your end product is 1.5 moles of KMnO 4 how many moles of manganese oxide were used in the reaction? The equation for the pro
vovikov84 [41]

Answer:

1.5 moles

Explanation:

The equation of the reaction is given as:

2 MnO2 + 4 KOH + O2 --> 2KMnO 4 + 2KOH + H2

From the equation,

2 moles of MnO2 produces 2 moles of KMnO4

x moles of MnO2 would produce 1.5 moles of KMnO4

2 = 2

x = 1.5

Solving for x;

x = 1.5 * 2 / 2

x = 1.5 moles

4 0
3 years ago
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