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3 years ago

Plz help quick

Chemistry

2 answers:

vovangra [49]3 years ago

4 0

Answer:

Explanation:

If oxygen reacts with iron, then both must be reactants and rust the product of that reaction

mariarad [96]3 years ago

4 0

Answer:

4Fe → 3O2 + 2Fe2O3

Explanation:

We see that the equation balances

There are 4 atoms of Iron (Fe) on the left and 2*2 = 4 on the right.

3 * 2 = 6 of oxygen on the left and 2 * 3 = 6 on the right.

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A detail that distinguishes a solid from a liquid is-------?

svetoff [14.1K]

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Group the following electron configurations in pairs that would represent similar chemical properties at their atoms;

marishachu [46]

<u>Answer:</u> Pairs are: (a) and (d), (b) and (f), (c) and (e)

<u>Explanation:</u>

In a periodic table, elements are arranged in 18 vertical columns known as groups and 7 horizontal rows known as periods.

Elements arranged in a group show similar chemical properties because of the presence of same number of valence electrons.

Valence electrons are defined as the electrons which are present in the outermost shell of an atom. Outermost shell has the highest value of 'n' that is principal quantum number.

For the given options:

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The given electronic configuration is: $1s^22s^22p^63s^2$

The number of valence electrons in the given configuration are 2

<u>For b:</u>

The given electronic configuration is: $1s^22s^22p^63s^3$

The number of valence electrons in the given configuration are [2 + 3] = 5

<u>For c:</u>

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The given electronic configuration is: $1s^22s^2$

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<u>For e:</u>

The given electronic configuration is: $1s^22s^22p^6$

The number of valence electrons in the given configuration are [2 + 6] = 8

<u>For f:</u>

The given electronic configuration is: $1s^22s^22p^63s^23p^3$

The number of valence electrons in the given configuration are [2 + 3] = 5

Electronic configuration of (a) and (d) will form a pair, (b) and (f) will form a pair, (c) and (e) will form a pair and will have similar chemical properties.

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3 years ago

At what temperature does 0.019135 moles of Ne in a 878.3 mL container exert a pressure of 0.946 atm?

Reika [66]

<h3>Answer:</h3>

Temperature is 529.164 K

<h3>Explanation:</h3>

We are given

Number of moles of Ne (n) = 0.019135 moles

Volume (V) = 878.3 mL

Pressure (P) = 0.946 atm

We are required to calculate the temperature;

We can do this using the ideal gas law equation which is;

PV = nRT, where P is the pressure, n is the number of moles, V is the volume, R is the ideal gas constant (0.082057 Latm/mol/K) and T is the temperature.

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$T=529.164 K$

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