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<span> the electron configuration for the manganese atom [Ne]3s</span>²
Answer:
34.3 g
Explanation:
Step 1: Write the balanced equation
2 CH₃CH₂OH ⇒ CH₃CH₂OCH₂CH₃ + H₂O
Step 2: Calculate the moles corresponding to 50.0 g of CH₃CH₂OH
The molar mass of CH₃CH₂OH is 46.07 g/mol.
50.0 g × 1 mol/46.07 g = 1.09 mol
Step 3: Calculate the theoretical moles of CH₃CH₂OCH₂CH₃ produced
The molar ratio of CH₃CH₂OH to CH₃CH₂OCH₂CH₃ is 2:1. The moles of CH₃CH₂OCH₂CH₃ theoretically produced are 1/2 × 1.09 mol = 0.545 mol.
Step 4: Calculate the real moles of CH₃CH₂OCH₂CH₃ produced
The percent yield of the reaction is 85%.
0.545 mol × 85% = 0.463 mol
Step 5: Calculate the mass corresponding to 0.463 moles of CH₃CH₂OCH₂CH₃
The molar mass of CH₃CH₂OCH₂CH₃ is 74.12 g/mol.
0.463 mol × 74.12 g/mol = 34.3 g
Answer:
Explanation:
Pipet is used to dispense a very small amount of liquid.
Test tube rack is used to hold multiple test tubes at the same time.
Test Table is used to view chemical reactions or hold or heat small amounts of substance.
Scoopula is used to dispense chemicals from a larger container.
Graduated cylinder is used to measure volume very precisely.
Bunsen burner is used to heat objects.
Beaker is used to transport heat or store substance.
Spot plate is used to observe the color changes of small quantities of a reacting mixture.
Goggles are used to protect the eyes from flying objects or chemical splashes.
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