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Kobotan [32]
3 years ago
8

1. Burning a candle is a chemical change. What is the primary evidence that burning the candle is a chemical reaction?

Chemistry
1 answer:
tankabanditka [31]3 years ago
8 0
<h2>Answer 1) Option B) Temperature Change</h2><h3>Explanation : </h3>

The burning of candle is the reaction where both physical and chemical changes occurs. A physical change where the melted wax is cooled and the wax is obtained again. Whereas the chemical change takes place when the wick of the candle burns using the oxygen in the air and produces heat and light. So, this change in temperature is a chemical change as the burning process cannot be reverse, from the burnt  products like soot, smoke and carbon dioxide. Therefore, the temperature change is the evidence of a chemical change in the burning of candle.

<h2>Answer 2) Option B) It is a chemical change because heat energy is absorbed and the pack gets colder.</h2><h3>Explanation :</h3>

When Clara is mixing the vial contents the ice pack gets colder. On application of the ice pack on the injured area absorbs the heat from that region and becomes more colder. This happens because in the ice pack was the medium for the temperature change that was occurring. This temperature change by absorbing heat getting colder is the evidence of a chemical change.

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What is the freezing point of a solution in which 2.50 grams of sodium chloride are added to 230.0 ml of water
labwork [276]

The freezing point of a solution in which 2.5 grams of NaCl is added t0 230 ml of water is :  - 0.69°C

<h3>Determine the freezing point of the solution </h3>

First step : Calculate the molality of NaCl

molality =  ( 2.5 grams / 58.44 g/mol ) / ( 230 * 10⁻³ kg/ml )

              = 0.186  mol/kg

Next step : Calculate freezing point depression temperature

T = 2 * 0.186 * kf

where : kf = 1.86°c.kg/mole

Hence; T = 2 * 0.186 * 1.86 = 0.69°C

Freezing point of the solution

Freezing temperature of solvent - freezing point depression temperature

                                               0°C  -  0.69°C = - 0.69°C

Hence the Freezing temperature of the solution is  - 0.69°C

Learn more about The freezing point of a solution in which 2.5 grams of NaCl is added t0 230 ml of water is :  - 0.69°C

8 0
2 years ago
Convert 15.5m³ to mL
ziro4ka [17]

Answer:

Explanation:

1.55e+7

3 0
1 year ago
A sample of tin (Cp = 0. 227 J/g•°C) is placed in a freezer. Its temperature decreases from 15. 0°C to â’10. 0°C as it rele
pshichka [43]

Taking into account the definition of calorimetry, the mass of the sample is 478.41 grams.

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

  • Q= -543 J because the energy is releases
  • c= 0.227 \frac{J}{gC}
  • m= ?
  • ΔT= Tfinal - Tinitial= 10 C - 15 C= -5 C

Replacing:

-543 J= 0.227 \frac{J}{gC}× m× (-5 C)

Solving:

m=\frac{-543 J}{0.227 \frac{J}{gC}x(-5 C)}

<u><em>m=478.41 grams</em></u>

In summary, the mass of the sample is 478.41 grams.

Learn more about calorimetry:

  • <u>brainly.com/question/11586486?referrer=searchResults </u>
  • <u>brainly.com/question/24724338?referrer=searchResults</u>
4 0
3 years ago
When NEM is added to a purified solution of creatine kinase, Cys 278 is alkylated, but no other Cys residues in the protein are
USPshnik [31]

Answer:

The answer is given below

Explanation:

Cys 278 residue is the only available cysteine which is alkylated  by the addition of N-Ethylmaleimide or NEM (alkylating agent). It works by only alkylating the sulfhydryls. In this case, Cys 278 residue is the only one which has exposed cysteine residue.

While the other residues have their sulfhydryls group either involved in the synthesis of disulfide bonds of proteins or their Cys residues are intrinsically placed in the proteins and cannot be alkylated with NEM.

NEM cannot alkylate if its protein is not available in the free form or it is in bounded form. For NEM to alkylate Cys 278, it should be free and should have sulfhydryls available for alkylation.

Alkylation: it is the transfer of alkyl groups. Alkyl groups contain Hydrogen and Carbon in their structure.

5 0
4 years ago
In the reaction of aluminum and iron(iii) oxide to form iron and aluminum oxide, δh is - 850 kj. how many grams of aluminum oxid
Semmy [17]
The  grams  of   aluminium  oxide  are  formed when  350  kj  heat  are  released is calculated  as  follows

1mole  =  850Kj
what  about  350kj
=1mole  x350/850  =  0.412  moles

mass  of  Al =   moles  of  Al x  molar  mass of  Al

=  0.412mol  x  27  g/mol  =  11.124  grams
8 0
3 years ago
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