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ANEK [815]
3 years ago
14

at 25C and 775 torr, Carbon dioxide has a solubility of 0.0347M in water. What is its solubility at 25C and 1270torr?

Chemistry
1 answer:
Maslowich3 years ago
7 0
Your answer is :
P = K * x where P is partial pressure K is Henry's constant and x is solubility 

<span>775 torr = K L·torr/mol * 0.0.0347 mole / liter </span>

<span>K = 775 / 0.0347 = 22334 L·torr/mol </span>

<span>in the second solution we have </span>

<span>1670 = 22334 * x </span>

<span>x = 1670 / 22334 </span>

<span>= 0.075 moles CO2 per liter of water.
</span>
Hope this helps :)
If you need anymore help with questions then feel free to ask me :D

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