the states of the reactants and products
the temperature and pressure at which the reaction was carried out
the relative amounts of reactants and products
the type of catalyst that is used to speed up the reaction
whether the reaction can go in both directions
Explanation:
A chemical equation is an equation that shows how the reactants are combining together to give the products.
The following are the information to include when writing a chemical equation;
- the states of the reactants and products
whether solid, liquid or gases or aqueous, It is usually appended as a subscript in bracket
- the temperature and pressure at which the reaction was carried out
this shows the condition under which the reaction was carried out. It also gives useful information that can be used to quantitatively determine heat changes in a reaction.
- the relative amounts of reactants and products
this is usually derived from the balanced equation. They are the numbers appended at the beginning of the species in the equation
- the type of catalyst that is used to speed up the reaction
it is a good practices to provide the information about the catalyst used.
- whether the reaction can go in both directions
→ signifies one direction
⇔ both directions
learn more:
Chemical equation brainly.com/question/2924195
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If in a redox reaction oxidation state of elements decreases or looses electron(s), the element is said to be oxidized. Hope this helps you!
Answer:
c.11.43 g of aluminum hydroxide
Explanation:
When the value of Ksp = 3.83 x 10^-11 (should be given - missing in your Q)
So, according to the balanced equation of the reaction:
and by using ICE table:
Ag2CrO4(s) → 2Ag+ (Aq) + CrO4^2-(aq)
initial 0 0
change +2X +X
Equ 2X X
∴ Ksp = [Ag+]^2[CrO42-]
so by substitution:
∴ 3.83 x 10^-11 = (2X)^2* X
3.83 x 10^-11 = 4 X^3
∴X = 2.1 x 10^-4
∴[CrO42-] = X = 2.1 x 10^-4 M
[Ag+] = 2X = 2 * (2.1 x 10^-4)
= 4.2 x 10^-4 M
when we comparing with the actual concentration of [Ag+] and [CrO42-]
when moles Ag+ = molarity * volume
= 0.004 m * 0.005L
= 2 x 10^-5 moles
[Ag+] = moles / total volume
= 2 x 10^-5 / 0.01L
= 0.002 M
moles CrO42- = molarity * volume
= 0.0024 m * 0.005 L
= 1.2 x 10^-5 mol
∴[CrO42-] = moles / total volume
= (1.2 x 10^-5)mol / 0.01 L
= 0.0012 M
by comparing this values with the max concentration that is saturation in the solution
and when the 2 values of ions concentration are >>> than the max values o the concentrations that are will be saturated.
∴ the excess will precipitate out
