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dybincka [34]
3 years ago
7

A car advertisement claims their car can go from a stopped position to moving 60 miles per hour in 5 seconds. The advertisement

is describing the car's
Physics
2 answers:
swat323 years ago
8 0
I do not understand what your saying could u plz be more specific?
alexandr402 [8]3 years ago
6 0

this is measuring the vehicles acceleration.

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The number of sound waves per unit time is called what
Andreyy89

Answer:

Frequency

Explanation:

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3 years ago
Why do you think the standards changed over time?
Eddi Din [679]

Answer:

https://www.quora.com/Why-do-you-think-standards-of-beauty-have-changed-over-the-years

Explanation:

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3 years ago
DETERMINE THE BCD EQUIVALENT OF 1100111110101001
Solnce55 [7]

Answer: It states that the BCD equivalent would be 0001000100000000000100010001000100010000000100000001000000000001.

6 0
2 years ago
*WILL MARK BRAINLIEST FOR RIGHT ANSWER* How much current must be applied across a 60 Ω light bulb filament in order for it to co
sp2606 [1]

Answer: The current must be equal to \frac{\sqrt{33} }{6} amps, or ~0.9574 amps.

Explanation:

You can find the current in amperes using ohms and watts from this formula:

I = \sqrt{\frac{P}{R} }

Where P represents power in watts, R represents resistance in ohms, and I represents current in amperes.

You can then substitute 60 and 55 into the equation to find I:

I = \sqrt{\frac{55}{60} } \\I = \frac{\sqrt{55} }{\sqrt{60} }

Then, simplify the denominator:

I = \frac{\sqrt{55} }{2\sqrt{15} }

Rationalize the denominator:

I = \frac{\sqrt{55} }{2\sqrt{15} } * \frac{\sqrt{15} }{\sqrt{15} } = \frac{\sqrt{825} }{30}

Simplify the numerator by finding its factors:

I = \frac{5\sqrt{33} }{30} = \frac{\sqrt{33} }{6}

The current must be equal to \frac{\sqrt{33} }{6} amps, or ~0.9574 amps.

8 0
3 years ago
Iron has a density of 7.8g/cm³. A solid iron statue has a mass of 877.5g. Work out the volume of the statue
Julli [10]

Answer:

112.5 cm

Explanation:

if mddddddbsmsjsixjxx

4 0
1 year ago
Read 2 more answers
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