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DiKsa [7]
3 years ago
10

Calculate the density of the football. Use the formula D = m/V where D is the density, m is the mass, and V is the volume. Recor

d your calculations in Table B of your Student Guide. What is the density of the football?
Physics
2 answers:
s344n2d4d5 [400]3 years ago
4 0

Answer:

Detailed explanation:

Density of water=1000kg/m³

Hence mass of water displaced is:

m=d×v

=1000kg/m³×(4.3×10^-3)m³ (volume of water displaced converted to L)

=4.3 kg of water

Hence, mass of football is also 4.3 kg(Archimedes principle)

Thus density of football

=mass÷volume

substitute the mass and volume and solve.

hope this helps

ddd [48]3 years ago
4 0

Answer:

0.10

Explanation:

I know because I got it right

You might be interested in
The boiling point of water is 91.30 °C on the
Taya2010 [7]

Answer:

196.34 °F

Explanation:

To convert from degrees celsius to degrees fahrenheit, use this equation:

(°C * 9/5) + 32 = °F

So, using this equation:

(91.30 * 9/5) + 32 = °F

196.34 + 32 = °F

°F = 196.34

Hope this helps!

3 0
3 years ago
What does a trench form?What happens here?
Vinvika [58]
A hole, and people die if they fall in there.
8 0
3 years ago
Which is the correct answer ?
hodyreva [135]
D ............................
7 0
4 years ago
Read 2 more answers
A 460 W heating unit is designed to operate with an applied potential difference of 120 V (a) By what percentage will its heat o
dybincka [34]

Answer:

(a) = -0.16%

(b) = smaller

Explanation:

given

power = 460 W

potential difference = 120 V

(a) what percentage will   its heat output drop if the applied potential difference drops to 110 V ?

we know p = \frac{v^2}{R} .....................(i)

we need to find change in power

\Delta P = \frac{\Delta (V^2)}{R}  

\Delta P = \frac{2 V \Delta V}{R}..............(ii)

from equations we get

\frac{\Delta P}{P} =  \frac{2 \Delta V}{V}

\frac{\Delta P}{P} = 2 \frac{110 -120}{120}

\frac{\Delta P}{P} =  -2(\frac{10}{120})

\frac{\Delta P}{P} = - 0.16 %

(b)

if we increase temperature resistance will increase and decrease with decrease in temperature and we know power is inversely proportional to resistance so if potential decrease and it would cause drop in power

and due to this increment of heating power resistance will decrease so actual drop in the power would  be smaller

7 0
3 years ago
What is the potential energy of a 3kg ball that is on the ground?
ELEN [110]

This is where we have to admit that gravitational potential energy is
one of those things that depends on the "frame of reference", or
'relative to what?'.

         Potential energy = (mass) x (gravity) x (<em>height</em>).

So you have to specify <em><u>height above what</u></em> .

-- With respect to the ground, the ball has zero potential energy.
(If you let go of it, it will gain zero kinetic energy as it falls to
the ground.)

-- With respect to the floor in your basement, the potential energy is

                 (3) x (9.8) x (3 meters) = 88.2 joules.

(If you let go of it, it will gain 88.2 joules of kinetic energy as it falls
to the floor of your basement.)

-- With respect to the top of that 10-meter hill over there, the potential
energy is
                    (3) x (9.8) x (-10) = -294 joules

(Its potential energy is negative. After you let go of it, you have to give it
294 joules of energy that it doesn't have now, in order to lift it to the top of
the hill <em>where it will have zero</em> potential energy.)


5 0
3 years ago
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