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statuscvo [17]
2 years ago
10

You want to build a snowman, so you accelerate a 2kg snowball across your yard at a rate of 0.5m/s2. Calculate the amount of for

ce you applied to your friend.

Physics
1 answer:
tamaranim1 [39]2 years ago
3 0

Answer:

4

Units:

Newtons

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All matter is made of particles; these can be single atoms or atoms chemically joined to make molecules. Using this fact, matter can be classified into three broad groups: elements, compounds and mixtures. In an element, all the atoms are of the same type. If more than one type of atom is chemically joined, then a compound has been formed. If more than one type of atom or molecule is contained in the same substance, and the particles aren't chemically joined, this is a mixture.

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On the way to school, Jed traveled 100m north, 300m east, 100 north, 100m east, and 100m north. A.) Find the total distance trav
Oduvanchick [21]

Answer:

Total distance = 700 m

Displacement = 500 m

Explanation:

Notice that Jed travelled a total of 3 x 100 m = 300 m in the North direction, and 300 m + 100 m = 400 m in the East direction. Therefore the total distance he travelled is:  300 + 400 = 700 m.

But the actual displacement is given by the Pythagorean theorem as the hypotenuse of a right angle triangle of legs 300 m and 400 m:

displacement = \sqrt{300^2+400^2} =\sqrt{250000} =500\,m

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Regions in the milky way where density waves have caused gas clouds to crash into each other are called
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Summarize renewable energy saves water and creates jobs
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4 0
3 years ago
A disk-shaped merry-go-round of radius 2.63 m and mass 152 kg rotates freely with an angular speed of 0.526 rev/s. A 51.7 kg per
zalisa [80]

 Explanation:

Given

radiusr=2.63 m

N=0.526 rev/s

\omega =3.30 rad/s

mass disc  M=152 kg

mass of person  m=51.7 kg

velocity of Person  v=2.76 m/s

moment of inertia  I=Mr^2

I=0.5\times 152\times 2.63^2=827.64 kg-m^2

Initial angular momentum

L_i=I\omega +mvr

L_i=827.64\times 3.30+51.7\times 2.76\times 2.63

L_i=2731.212+375.27=3106.48 Js

Final Moment inertia

I_f=0.5Mr^2+mr^2

I_f=(152\cdot 0.5+51.7)\cdot (2.63)^2=1185.243 kg-m^2

final angular momentum

L_f=I_f\omega _f

Conserving angular momentum

L_i=L_f

3106.48=1408.97\times \omega _f

\omega _f=2.62 rad/s

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3 years ago
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