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Lady bird [3.3K]
3 years ago
13

A girl and boy pull in opposite directions on a stuffed animal. The girl exerts a force of 3.5 N. The mass of the stuffed animal

is 0.2 kg, and it is accelerating to the right 2.5 m/s2. What is the force that the boy is exerting?
Physics
2 answers:
Dmitry [639]3 years ago
3 0
The resultant force on the animal = Resultant mass * total acceleration 
F = 0.2 * 2.5 to the right
F = 0.5 to the right.

As, girl exerting a force of 3.5 N & it's not mentioned that she is in right or left, so the force exerting by boy would be either:
3.5-0.5 = 3  OR  3.5+0.5 = 4

If boy exerting a greater force then, answer will be 4 N & if girl exerting a greater force the, answer will be 3 N

Hope this helps!
xxMikexx [17]3 years ago
3 0
The correct answer is 4. 

2.5 x .2 = .5

3.5N + .5N = 4N 
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Newtons first law 1 to 5. <br>What is each of the net force for all of the 5 questions? ​
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Explanation:

1. Determination of the net force.

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Net force (Fₙ) =?

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Fₙ = 35 + 125

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3. Determination of the net force.

Force applied to the right (Fᵣ) = 75 N

Force applied to the left (Fₗ) = 75 N

Net force (Fₙ) =?

Fₙ = Fₗ – Fᵣ

Fₙ = 75 – 75

Fₙ = 0

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4. Determination of the net force.

Force 1 applied to the right (F₁) = 150 N

Force 2 applied to the right (F₂) = 60 N

Net force (Fₙ) =?

Fₙ = F₁ + F₂

Fₙ = 150 + 60

Fₙ = 210 N

Thus, the net force is 210 N.

5. Determination of the net force.

Force applied to the right (Fᵣ) = 115 N

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Fₙ = Fᵣ – Fₗ

Fₙ = 115 – 25

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