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Verdich [7]
2 years ago
14

PLEASE HELP!! WILL MARK BRAINLEST!!! What are 3 types of waves?

Physics
1 answer:
Maslowich2 years ago
8 0

Answer:

transverse waves, longitudinal waves, and surface waves.

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A train car with mass m1 = 515 kg is moving to the right with a speed of v1 = 7.5 m/s and collides with a second train car. The
Anna [14]

Answer:

For the first situation, we first need to find the mass of the second train car.

In order to do that, we apply the conservation of the amount of movement:

515*7.5+m2*0=(m1+m2)*4.8

and we have as a result:

m2 = 289.6875

For the second situation, also we will apply the conservation of the amount of movement:

515*7.5-289.6875*6 = (515+289.6875)*V

and we have as a result:

V = 2.64 (it is moving to the right)

6 0
3 years ago
Brainliest if correct
poizon [28]

Answer:

A

Explanation:

hope it helps you make brainliest

3 0
2 years ago
Read 2 more answers
Which of the following is known as the use of a wave?
TiliK225 [7]

Answer:

Explanation:

Waves involve the transport of energy without the transport of matter. In conclusion, a wave can be described as a disturbance that travels through a medium, transporting energy from one location (its source) to another location without transporting matter.

7 0
3 years ago
What frequency is received by the ambulance after reflecting from a wall near the person watching the oncoming ambulance (as in
Zepler [3.9K]

Answer:

900.48925 Hz

979.9785 Hz

Explanation:

v_a = Relative velocity of ambulance =109\ km/h=\dfrac{109}{3.6}

v_w = Velocity of wall = 0

v = Velocity of sound in air = 343 m/s

From doppler effect we have

f=f'\dfrac{v+v_w}{v-v_a}\\\Rightarrow f=821\dfrac{343+0}{343-\dfrac{109}{3.6}}\\\Rightarrow f=900.48925\ Hz

The frequency of sound is 900.48925 Hz

When the wall acts like a source

f=f'\dfrac{v+v_a}{v-v_w}\\\Rightarrow f=900.48925\dfrac{343+\dfrac{109}{3.6}}{343-0}\\\Rightarrow f=979.9785\ Hz

The frequency of sound is 979.9785 Hz

4 0
3 years ago
La trayectoria de vuelo del helicóptero cuando despega desde A esta definida por las ecuaciones x=2t^2 m y y=0.04t^3 m, donde t
Yuri [45]

Answer:

The flight path of the helicopter when it takes off from A is defined by the equations x = 2t ^ 2 m and y = 0.04t ^ 3 m, where t is the time in seconds. Determine the distance the helicopter is from point A and the magnitudes of its speed and acceleration when t = 10 s

Explanation:

Given that,

The path curve are

x = 2t²

y = 0.04t³

Distance from A. When t = 10s

The position on the x axis at t=10s is

x = 2t²

x = 2×10² = 200m

The position on y axis at t= 10s is

y = 0.04t³

y = 0.04 ×10³ = 40m

So, the plane it at (200,40) and it started for (0,0)

From geometry we can find distance between the two point using

D = √(x2-x1)² + (y2-y1)²

D = √(200-0)²+(40-0)²

D = √200²+40²

D = 203.96m

So, the distance is approximately 204m

b. The magnitude of the speed.

Speed is give as the differentiation of distance

So, for x curve, at t =10

Vx = dx/dt = 4t

Vx = 4×10 = 40m/s

Also, for y axis at t=10

Vy = dy/dt = 0.12t²

Vy = 0.12×10² = 12m/s

Then, the velocity at 10s is

V = √(Vx²+Vy²)

V = √40²+12²

V = 41.76m/s

The velocity helicopter at t=10s is 41.76m/s

c. The acceleration at t=10s?

We need to find acceleration of the curve and it is given as

a = d²x/dt²

So, for x axis at t=10

ax= d²x/dt² = 4

ax = 4m/s²

Also, for y axis at t=10

ay= d²y/dt² = 0.24t

ay = 0.24 ×10 = 2.4m/s²

Then, the magnitude of acceleration at t=10s is

a = √(ay²+ax²)

a = √2.4²+ 4²

ay = 4.66m/s²

The acceleration of the helicopter at t=10s is 4.66m/s²

4 0
3 years ago
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