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Natali5045456 [20]
3 years ago
15

Which of the following measure would remain consistent no matter it's location?

Chemistry
2 answers:
elena55 [62]3 years ago
4 0
Mass using grams because of the balance scale is evenly weighted not from springs and gravity like a normal scale.
Jlenok [28]3 years ago
4 0
<h2>Answer : Mass of an object</h2><h3>Explanation :</h3>

Mass of an object will remain consistent no matter it's location. Mass is usually a measurement of matter in an object. It has both the property of a physical body and also the measure of its resistance to acceleration on application of a net force.

It helps to determine the strength between two bodies with mutual gravitational attraction. The units of mass is kilogram. Mass does not changes with the location whereas weight is found to be changes with location like space and earth.

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An abandoned Indiana coal mine spoil bank (wastes) contains chunks of pyrite minerals. Under constant erosion and weathering, th
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The acid will be neutralized overtime

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A 2. 75-l container filled with co2 gas at 25°c and 225 kpa pressure springs a leak. When the container is re-sealed, the pressu
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The number of moles of gas lost is  0.0213 mol. It can be solved with the help of Ideal gas law.

<h3>What is Ideal law ?</h3>

According to this law, "the volume of a given amount of gas is directly proportional to the number on moles of gas, directly proportional to the temperature and inversely proportional to the pressure. i.e.

PV = nRT.

Where,

  • p = pressure
  • V = volume (1.75 L = 1.75 x 10⁻³ m³)
  • T =  absolute temperature
  • n = number of moles
  • R =  gas constant, 8.314 J*(mol-K)

Therefore, the number of moles is

n = PV / RT

State 1 :

  • T₁ = (25⁰ C = 25+273 = 298 K)
  • p₁ = 225 kPa = 225 x 10³ N/m²

State 2 :

  • T₂ = 10 C = 283 K
  • p₂ = 185 kPa = 185 x 10³ N/m²

The loss in moles of gas from state 1 to state 2 is

Δn = V/R (P₁/T₁ - P₂/T₂ )

V/R = (1.75 x 10⁻³ m³)/(8.314 (N-m)/(mol-K) = 2.1049 x 10⁻⁴ (mol-m²-K)/N

p₁/T₁ = (225 x 10³)/298 = 755.0336 N/(m²-K)

p₂/T₂ = (185 x 10³)/283 = 653.7102 N/(m²-K)

Therefore,

Δn = (2.1049 x 10⁻⁴ (mol-m²-K)/N)*(755.0336 - 653.7102 N/(m²-K))

    = 0.0213 mol

Hence, The number of moles of gas lost is 0.0213 mol.

Learn more about ideal gas here ;

https://brainly.in/question/641453

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