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3 years ago

Select the single best answer. Which mechanism properly shows the movement of electrons in the reaction? 2xsafari

Chemistry

1 answer:

sweet [91]3 years ago

5 0

Answer:

Explanation:

We must study the reaction pictured in the question closely before we begin to attempt to answer the question.

Now, the reaction is a free radical reaction. This implies that only one electron is transferred. The transfer of one electron is shown using a half arrow rather than a full arrow. The both species are radicals (odd electron species) and contribute one electron each.

Hence we must show electron movements in both species using a half arrow.

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Which part of the electrochemical cell allows the back-and-forth passage of ions from the cathode to the anode? the half cell

olganol [36]

Answer is "The salt Bridge"

Explanation:
During the spontaneous reaction in Voltaic Cell, the balance of ions get disturb due to increase in concentration of negative charge in one half cell and positive charge in another. In order to keep balance the charges in cell, concentration of ions on both sides and overall neutrality of the system, a U-shape tube filled with inert electrolyte is connected to both half cells. The electrolyte migrates in such a way that the charges of solution in cells keep constant.

6 0

3 years ago

Solve for C. C = K -273 K= 37

brilliants [131]

C= -236

Explanation:

k=37.

37-273. 273-37=236

37-273= -236

THEREFORE

The value of C is -236

8 0

2 years ago

What is the major ion in seawater?

Dmitrij [34]

Answer:

It should be chloride I am almost positive

Explanation:

Typical Seawater

Chloride (Cl-) 18.980

Sodium (Na+) 10.556

Sulfate (SO42-) 2.649

Magnesium (Mg2+) 1.262

4 0

3 years ago

A buffer with a pH of 4.31 contains 0.31 M of sodium benzoate and 0.24 M of benzoic acid. What is the concentration of [ H 3 O ]

Mnenie [13.5K]

Answer: The hydronium ion concentration in the solution is $1.29\times 10^{-4}M$

Explanation:

To calculate the molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Moles hydrochloric acid solution = 0.060 mol

Volume of solution = 1 L

Putting values in above equation, we get:

$\text{Molarity of HCl}=\frac{0.060}{1L}\\\\\text{Molarity of HCl}=0.060M$

The chemical reaction for aniline and HCl follows the equation:

$C_6H_5COO^-+HCl\rightarrow C_6H_5COOH+Cl^-$

Initial: 0.24 0.060 0.31

Final: 0.18 - 0.37

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[\text{conjugate acid}]}{[\text{base}]})$

$pH=pK_a+\log(\frac{[C_6H_5COO^-]}{[C_6H_5COOH]})$

We are given:

$pK_a$ = negative logarithm of acid dissociation constant of benzoic acid = 4.2

$[C_6H_5COO^-]=0.18M$

$[C_6H_5COOH]=0.37M$

pH = ?

Putting values in equation 1, we get:

$pH=4.2+\log(\frac{0.18}{0.37})\\\\pH=3.89$

To calculate the hydronium ion concentration in the solution, we use the equation:

$pH=-\log[H_3O^+]$

pH = 3.89

Putting values in above equation, we get:

$3.89=-\log[H_3O^+]$

$[H_3O^+]=10^{-3.89}=1.29\times 10^{-4}M$

Hence, the hydronium ion concentration in the solution is $1.29\times 10^{-4}M$

3 0

3 years ago

How is shielding effect related to atomic radius?

jolli1 [7]

Shielding effect being attendency of the inner electrons to repel the outermost electrons, an increase in shielding effect increases atomic radius and decrease reduces the atomic radius

7 0

3 years ago