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goldenfox [79]
3 years ago
14

Select the single best answer. Which mechanism properly shows the movement of electrons in the reaction? 2xsafari

Chemistry
1 answer:
sweet [91]3 years ago
5 0

Answer:

D

Explanation:

We must study the reaction pictured in the question closely before we begin to attempt to answer the question.

Now, the reaction is a free radical reaction. This implies that only one electron is transferred. The transfer of one electron is shown using a half arrow rather than a full arrow. The both species are radicals (odd electron species) and contribute one electron each.

Hence we must show electron movements in both species using a half arrow.

You might be interested in
The following molecular equation represents the reaction that occurs when aqueous solutions of silver(I) nitrate and calcium chl
dsp73

Answer:

Ag+(aq) + Cl-(aq) —> AgCl(s)

Explanation:

2AgNO3(aq) + CaCl2(aq) —>2AgCl(s) + Ca(NO3)2(aq)

The balanced net ionic equation for the reaction above can be obtained as follow:

AgNO3(aq) and CaCl2(aq) will dissociate in solution as follow:

AgNO3(aq) —> Ag+(aq) + NO3-(aq)

CaCl2(aq) —> Ca2+(aq) + 2Cl-(aq)

AgNO3(aq) + CaCl2(aq) –>

2Ag+(aq) + 2NO3-(aq) + Ca2+(aq) + 2Cl-(aq) —> 2AgCl(s) + Ca2+(aq) + 2NO3-(aq)

Cancel out the spectator ions i.e Ca2+(aq) and 2NO3- to obtain the net ionic equation.

2Ag+(aq) + 2Cl-(aq) —> 2AgCl(s)

Divide through by 2

Ag+(aq) + Cl-(aq) —> AgCl(s)

The, the net ionic equation is

Ag+(aq) + Cl-(aq) —> AgCl(s)

4 0
3 years ago
Calculate the molarity of a solution prepared by
lions [1.4K]

Answer:

Molarity= 0.414M

Explanation:

Applying dilution formula

C1V1=C2V2

0.9×0.575= C2× 1.25

C2= 0.414M

4 0
3 years ago
a metal object has a mass of 9.0g and a volume of 1.5ml. what is the density of the object? density= mass/volume​
weeeeeb [17]

The density of the metal object=6.0\frac{g}{m l}

Given:

Volume of the metal object=1.5ml

Mass of the metal object=9.0g

To find:

Density of the metal object

<u>Step by Step Explanation: </u>

Solution:

According to the formula, Density of the metal object can be calculated as

\rho=\frac{m}{v}

Where, m=mass of the metal object

\rho =density of the metal object

v=volume of the metal object

We know the values of v=1.5ml and m=9.0g

Substitute these values in the above equation we get

\rho=\frac{m}{v}

\rho=9.0/1.5

=6.0\frac{g}{m l}

Result:

Thus the density of the metal object is 6.0\frac{g}{m l}

4 0
3 years ago
How many moles of a gas sample are in a 5.0 L container at 205 K and 340 kPa?
Mazyrski [523]

Answer:

1.0 mole

Explanation:

From the question given above, the following data were obtained:

Volume (V) = 5 L

Temperature (T) = 205 K

Pressure (P) = 340 KPa

Gas constant (R) = 8.31 KPa.L/Kmol

Number of mole (n) =?

Using the ideal gas equation, the number of mole of the gas in the container can be obtained as follow:

PV = nRT

340 × 5 = n × 8.31 × 205

1700 = n × 1703.55

Divide both side by 1703.55

n = 1700 / 1703.55

n = 1.0 mole

Thus, the number of mole of the gas in the container is 1.0 mole

3 0
2 years ago
A sample of an ideal gas has a volume of 2.31 l at 287 k and 1.10 atm. calculate the pressure when the volume is 1.45 l and the
balu736 [363]
Hello!

The pressure of the Ideal Gas when the volume is 1,45 L and the temperature is 298 K is 1,82 atm.

To solve this problem we need to apply the Ideal Gas Law for the initial conditions and the final ones, clearing the equation for the number of moles (n) and the ideal gas constant (R) which remain constant:

P_n*V_n=n*R*T_n \\ \\ n*R= \frac{P_n*V_n}{T_n}

Now we match n*R for the initial conditions (1) and the final ones (2), clearing the equation for P₂

\frac{P_1*V_1}{T_1}= \frac{P_2*V_2}{T_2} \\ \\ P_2= \frac{P_1*V_1*T_2}{T_1*V_2}= \frac{1,10 atm*2,31 L *298 K}{287K*1,45 L}=1,82 atm

Have a nice day!

7 0
3 years ago
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