Answer:
Ag+(aq) + Cl-(aq) —> AgCl(s)
Explanation:
2AgNO3(aq) + CaCl2(aq) —>2AgCl(s) + Ca(NO3)2(aq)
The balanced net ionic equation for the reaction above can be obtained as follow:
AgNO3(aq) and CaCl2(aq) will dissociate in solution as follow:
AgNO3(aq) —> Ag+(aq) + NO3-(aq)
CaCl2(aq) —> Ca2+(aq) + 2Cl-(aq)
AgNO3(aq) + CaCl2(aq) –>
2Ag+(aq) + 2NO3-(aq) + Ca2+(aq) + 2Cl-(aq) —> 2AgCl(s) + Ca2+(aq) + 2NO3-(aq)
Cancel out the spectator ions i.e Ca2+(aq) and 2NO3- to obtain the net ionic equation.
2Ag+(aq) + 2Cl-(aq) —> 2AgCl(s)
Divide through by 2
Ag+(aq) + Cl-(aq) —> AgCl(s)
The, the net ionic equation is
Ag+(aq) + Cl-(aq) —> AgCl(s)
Answer:
Molarity= 0.414M
Explanation:
Applying dilution formula
C1V1=C2V2
0.9×0.575= C2× 1.25
C2= 0.414M
The density of the metal object=6.0
Given:
Volume of the metal object=1.5ml
Mass of the metal object=9.0g
To find:
Density of the metal object
<u>Step by Step Explanation:
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Solution:
According to the formula, Density of the metal object can be calculated as

Where, m=mass of the metal object
=density of the metal object
v=volume of the metal object
We know the values of v=1.5ml and m=9.0g
Substitute these values in the above equation we get

=9.0/1.5
=6.0
Result:
Thus the density of the metal object is 6.0
Answer:
1.0 mole
Explanation:
From the question given above, the following data were obtained:
Volume (V) = 5 L
Temperature (T) = 205 K
Pressure (P) = 340 KPa
Gas constant (R) = 8.31 KPa.L/Kmol
Number of mole (n) =?
Using the ideal gas equation, the number of mole of the gas in the container can be obtained as follow:
PV = nRT
340 × 5 = n × 8.31 × 205
1700 = n × 1703.55
Divide both side by 1703.55
n = 1700 / 1703.55
n = 1.0 mole
Thus, the number of mole of the gas in the container is 1.0 mole
Hello!
The pressure of the Ideal Gas when the volume is 1,45 L and the temperature is 298 K is
1,82 atm.
To solve this problem we need to apply the
Ideal Gas Law for the initial conditions and the final ones, clearing the equation for the number of moles (n) and the ideal gas constant (R) which remain constant:

Now we match n*R for the initial conditions (1) and the final ones (2), clearing the equation for P₂

Have a nice day!