Explanation:
A chemical property is defined as the property that brings changes in chemical composition of a substance.
For example, flammability, combustion, reactivity, electronegativity etc are allchemical properties.
On the other hand, a property that does not bring any change in chemical composition of a substance is known as a physical property.
For example, shape, size, mass, density etc are all physical properties.
Thus, we can conclude that these may all be classified as chemical properties of a substance.
Answer: Ti is the reducing agent because it changes from 0 to +4 oxidation state.
Explanation:
- Firstly, we need to identify the reducing agent and the oxidizing agent.
- The reducing agent: is the agent that has been oxidized via losing electrons.
- The oxidizing agent: is the agent that has been reduced via gaining electrons.
- Here, Ti losses 4 electrons and its oxidation state is changed from 0 to +4 and Cl₂ gains one electron and its oxidation state is changed from 0 to -1.
- So, Ti is the reducing agent because its oxidation state changes from 0 to +4.
- Cl₂ is the oxidizing agent because its oxidation state changes from 0 to -1.
- Thus, The right answer is Ti is the reducing agent because it changes from 0 to +4 oxidation state.
We balance the given reactions above by following the rules in balancing redox reactions in acidic or basic solutions. Balance the atoms aside from the O and H atoms. Then we balance the Os and Hs by adding H2O or H+. Finally, we balance the total charge of the reactant and product by adding e-. We do as follows:
<span>A) H2O2 + Fe 2+ ---> Fe 3+ + H2O (in the acidic solution)
</span><span> 2H+ + </span>H2O2 + Fe 2+ ---> Fe 3+ + 2H2O
e- + 2H+ + H2O2 + Fe 2+ ---> Fe 3+ + 2H2O
<span>
C) CN- + MnO4- ---> CNO- +MnO2 (in basic solution)
</span> CN- + MnO4- ---> CNO- +MnO2 + H2O
2H+ + CN- + MnO4- ---> CNO- +MnO2 + H2O
2OH- + 2H+ + CN- + MnO4- ---> CNO- +MnO2 + H2O + 2OH-
2H2O + CN- + MnO4- ---> CNO- +MnO2 + H2O + 2OH-
e- + H2O + CN- + MnO4- ---> CNO- +MnO2 + 2OH-
<span>
E) S2O2/3- + I2 ---> I- + S4O2/6- (in acidic solution)
2</span>S2O2/3- + I2 ---> 2I- + S4O2/6-
4H+ + 2S2O2/3- + I2 ---> 2I- + S4O2/6- + 2H2O
6e- + 4H+ + 2S2O2/3- + I2 ---> 2I- + S4O2/6- + 2H2O
