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Dahasolnce [82]
3 years ago
12

34

Chemistry
1 answer:
ddd [48]3 years ago
7 0

Answer:

116 °C

Explanation:

The given parameters of the Substance Q are;

The boiling point of Q = 445°

The substance <em>Q</em> is a solid at room temperature

Given that <em>Q</em> has a single fixed boiling point, <em>Q</em>, is suspected to be a pure substance, and it will therefore also have a fixed single melting point above room temperature;

Therefore, the best option is option C. 116 °C, which is above a single temperature value above 116 °C

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Which one of these complementary base pairs can form three hydrogen bonds?
ValentinkaMS [17]

Answer:

Option D is the correct answer

Explanation:

There are three hydrogen bonds formed between Guanine and Cytosine base.  

The first hydrogen bond is formed between the oxygen atom on Carbon-6 (C-6) of guanine, and one of the hydrogen atoms attached to the Nitrogen atom (i.e the one of the hydrogen atoms in the amino group) on the Carbon-4 (C-4)of the cytosine base.  

The second hydrogen bond is formed between the hydrogen atom on Nitrogen-1 (N-1) of the guanine base and Nitrogen-3 (N-3) of the cytosine base.

The third hydrogen bond exist between one of the hydrogen atoms in the amino group attached to the second Carbon (C-2) of the guanine base, and the oxygen atom attached to the second Carbon (C-2) of the cytosine base.  

7 0
3 years ago
Carbon dioxide (CO2) is a gaseous compound. Calculate the percent composition of this compound. Answer using three significant f
Tamiku [17]

Carbon dioxide is a gaseous molecule made up of the elements, C and O. Each mole of carbon dioxide has one mole C and two mole oxygen atoms.

Molar mass of carbon dioxide (CO_{2})=(1 * 12.01\frac{g}{mol}) +(2* 16\frac{g}{mol})=44.01\frac{g}{mol}

Percentage by mass of carbon = \frac{(1*12.01\frac{g}{mol}) }{44.01\frac{g}{mol} } *100=27.3%

Percentage by mass of oxygen = \frac{(2*16\frac{g}{mol})}{44.01\frac{g}{mol} } *100=72.7%

Therefore C is 27.3 % and O is 72.7 % by mass in 1 mol CO_{2}

7 0
3 years ago
Read 2 more answers
He orbital period of an object is 2 × 107 s and its total radius is 4 × 1010 m
gtnhenbr [62]

Answer:

The answer is 12,560  

Explanation:

The orbital period is the time a given cosmic question takes to finish one circle around another protest and applies in space science as a rule to planets or space rocks circling the Sun, moons circling planets, exoplanets circling different stars, or double stars. Mercury, for instance, has an orbital time of 88 days while it takes Jupiter around 11.86 years. The time of the Earth's circle is generally thought to be 365 days as timetables appear.

6 0
3 years ago
Read 2 more answers
Osmium is the most dense element we know of. A 22 g sample of Osmium has a volume of 100 cL. Calculate the density of Osmium in
kakasveta [241]

Answer:

a. V = 1000 mL

b. Denisty = 0.022 g/mL

Explanation:

a.

First we need to convert the volume of the Osmium into mL. For that purpose we are given the conversion unit as:

1 mL = 0.1 cL

Hence, the given volume of Osmium will be:

V = Volume of Osmium = 100 cL = (100 cL)(1 mL/0.1 cL) = 1000 mL

<u>V = 1000 mL</u>

b.

The density of Osmium is given by the following formula:

Density = mass/Volume

Denisty = 22 g/1000 mL

<u>Denisty = 0.022 g/mL</u>

5 0
3 years ago
Which of the following is defined as the mass of an atom based on the mass of an atom of carbon-12?
iogann1982 [59]
<span>This would be the atomic mass. In an atom of carbon-12, there are 6 protons and 6 neutrons at rest (electrons have a negligible mass and are usually not part of the overall mass calculation). All atomic masses are based off the measurements of this specific iteration of carbon.</span>
3 0
3 years ago
Read 2 more answers
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