Answer:
∆S = ∆H / T = 17.2 kJ/mol (298 K)
∆S = 0.0577 kJ/mol K
∆S = 0.0577 kJ/mol K x 1.41 moles = 0.0814 kJ/K = 81.4 J/K
1.41 mol x 17.2 kJ/mol = 24.25 kJ
∆S = 24.25 kJ / 298 K = 0.0814 kJ/K = 81.4 J/K
Explanation:
Answer:
Given,
Maas of the man = 80 kg
Percentage of water molecules it contains = 70%
Therefore,
Total no. of water molecules mass present in our human body
Answer - The total number of water molecules present in our body is 56 kg.
Hope it helps you!!
#IndianMurga
i can not understand the question. There seems to be missing info
You can solve this problem through dimensional analysis.
First, find the molar mass of NaHCO3.
Na = 22.99 g
H = 1.008 g
C = 12.01 g
O (3) = 16 (3) g
Now, add them all together, you end with with the molar mass of NaHCO3.
22.99 + 1.008 + 12.01 + 16(3) = 84.008 g NaHCO3. This number means that for every mole of NaHCO3, there is 84.008 g NaHCO3. In simpler terms, 1 mole NaHCO3 = 84.008 g NaHCO3.
After finding the molar mass of sodium bicarbonate, now you can use dimensional analysis to solve for the number of moles present in 200. g of sodium bicarbonate.
Cross out the repeating units which are g NaHCO3, and the remaining unit is mole NaHCO3
200. * 1 = 200
200/ 84.008 = 2.38
Notice how there are only 3 sig figs in the answer. This is because the given problem only gave three sig figs.
Your final answer is 2.38 mol NaHCO3.
Filtration, is a chemical process where you are separating a precipitate from a solution.
As a general rule:
"Solubility of compounds decrease with the increasing of temperature" as you can see in the graph
Now, if you want to recover benzoic acid from an aqueous solution, the better option would be with Ice cold water because its solubility will be lower producing more precipitate.
Learn more about this process in:
brainly.com/question/14918321