Swinging a golf club toward a golf<br> ball and hitting it off the tee.

A student dissolves 15.g of sucrose C12H22O11 in 300.mL of a solvent with a density of 1.13/gmL. The student notices that the vo

Kruka [31]

<u>Answer:</u> The molarity and molality of sucrose solution is 0.146 M and 0.129 m respectively

<u>Explanation:</u>

<u>Calculating the molarity of solution:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Given mass of sucrose = 15 g

Molar mass of sucrose = 342.3 g/mol

Volume of solution = 300 L

Putting values in above equation, we get:

$\text{Molarity of sucrose solution}=\frac{15\times 1000}{342.3\times 300}\\\\\text{Molarity of sucrose solution}=0.146M$

Hence, the molarity of sucrose solution is 0.146 M

<u>Calculating the molality of solution:</u>

To calculate the mass of solvent, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of solvent = 1.13 g/mL

Volume of solvent = 300 mL

Putting values in above equation, we get:

$1.13g/mL=\frac{\text{Mass of solvent}}{300mL}\\\\\text{Mass of solvent}=(1.13g/mL\times 300mL)=339g$

To calculate the molality of solution, we use the equation:

$\text{Molality of solution}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

where,

$m_{solute}$ = Given mass of solute (sucrose) = 15 g

$M_{solute}$ = Molar mass of solute (sucrose) = 342.3 g/mol

$W_{solvent}$ = Mass of solvent = 339 g

Putting values in above equation, we get:

$\text{Molality of solution}=\frac{15\times 1000}{342.3\times 339}\\\\\text{Molality of solution}=0.129m$

Hence, the molality of sucrose solution is 0.129 m

5 0

4 years ago

Helpppppppppppppp plllllllzzzzzzzzzz

Serggg [28]

4Fe+3O₂⇒2Fe₂O₃

CO₂+2Cl₂⇒O₂+CCl₄

<h3>Further explanation </h3>

Equalization of chemical reactions can be done using variables. Steps in equalizing the reaction equation:

1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c, etc.

2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index (subscript) between reactant and product

3. Select the coefficient of the substance with the most complex chemical formula equal to 1

For simple equations, you can experiment with the balance of the number of atoms on the left and right

4Fe+3O₂⇒2Fe₂O₃

CO₂+2Cl₂⇒O₂+CCl₄

with variable :

aFe+bO₂⇒Fe₂O₃

Fe , left=a, right=2⇒a=2

O, left=2b, right=3⇒2b=3⇒b=3/2

the equation :

2Fe+3/2O₂⇒Fe₂O₃ x2

4Fe+3O₂⇒2Fe₂O₃

aCO₂+bCl₂⇒O₂+CCl₄

C, left=a, right=1⇒a=1

Cl, left=2b, right=4⇒b=2

O, left=2a, right=2⇒2a=2⇒a=1

the equation :

CO₂+2Cl₂⇒O₂+CCl₄

8 0

3 years ago

What is the mass in grams of 1.00*10^12 lead atoms

pav-90 [236]

34.5 X 10^-11 grams of lead

5 0

3 years ago

Balance the single replacement chemical reaction.

OLEGan [10]

Answer:

Option c. 2Kl + Cl2 —> 2KCl + l2

Explanation:

A balanced equation must have the same number of atoms on the reactants side and the products side. This do the fact of the postulation by the mass conservation principle that says: Atoms can neither be broken nor destroyed but can be arranged. The atoms on the left side for each element are equal. Thus, C presents a balanced equation.

3 0

4 years ago

What makes the atomic radius change down a column of the periodic table

Olin [163]

As you go across a period, radius shrinks because you are adding protons. The added positive charge increases pull on the electron shells.

As you go down a group, radius gets larger because you are increasing shells of electrons. This increases shielding of the nucleus' positive charge, so the electrons are not pulled in as much.

8 0

3 years ago

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